如何将数据库值分配给详细信息视图项模板标签 [英] How to assign Database value to Detail view item Template label

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问题描述


您能否更正以下代码

我必须从数据库中获取价值并将其分配给Detailview项目模板标签

Hi
Could you please correct the below code

I have to take value from database and assign it to Detailview item template label

 <fields>                                                                    <asp:TemplateField HeaderText="Company Name">
                                                                        <itemtemplate>
                                                                            <asp:Label ID="complbl" Text = "Hi" runat = "server">
                                                                        </itemtemplate>
                                                                      
                                                                    <asp:TemplateField HeaderText="Company Address">
                                                                        <itemtemplate>
                                                                            <asp:Label ID="addlbl" runat="server" Visible="true">
                                                                        </itemtemplate>
                                                                                                                                        
</fields>                                                                


while (reader.Read())
        {
            doDate = reader["DoDate"].ToString();
            doNumber = reader["DoNumber"].ToString();
            customerId = reader["CusId"].ToString();
            comp = reader["CompName"].ToString();

            

            DoNotb.Text = doNumber;
            doDatetb.Text = doDate;
            cidtb.Text = customerId;
            Label compname = DetailsView1.Rows[1].Cells[0].FindControl("complbl");
            comp = compname.Text;
            compname.Text = comp;
 
        }



我收到错误消息,因为"



I am getting error as "

Index was out of range. Must be non-negative and less than the size of the collection.
Parameter name: index



Thanks



Thanks

推荐答案

更正后的代码为
Corrected code as
Collapse | Copy Code
 <fields>                                                                    <asp:TemplateField HeaderText="Company Name">
                                                                        <itemtemplate>
                                                                            <asp:Label ID="complbl" Text = "Hi" runat = "server" text='<%# Eval("complbl")%>' >
                                                                        </itemtemplate>

                                                                    <asp:TemplateField HeaderText="Company Address">
                                                                        <itemtemplate>
                                                                            <asp:Label ID="addlbl" runat="server" Visible="true"  text='<%# Eval("complbl")%>' >

                                                                        </itemtemplate>

</fields>


 <fields>                                                                    
   <asp:templatefield headertext="Company Name" xmlns:asp="#unknown">
        <itemtemplate>
            <asp:label id="complbl" Text='<%# Eval("complbl")%>' runat="server">
        </itemtemplate>
                                                                      
        <asp:templatefield headertext="Company Address">
        <itemtemplate>
        <asp:label id="addlbl" runat="server" Text='<%# Eval("compAddress")%>' visible="true">
        </itemtemplate>
</fields>



在服务器端,您只需要将数据表分配给gridview的DataSource.
DataTable中应该有complbl,compAddress列

让我知道是否有任何疑问
如果解决了您的问题,请标记为解决方案



At Server side you just need to assign datatable to DataSource of gridview.
There should be column complbl,compAddress in DataTable

let me know if any queries
Mark as solution if its solved your problem


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