使用Borland 32位的C ++源代码 [英] C++ source code using Borland 32 bits
本文介绍了使用Borland 32位的C ++源代码的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在使用7 os 64位窗口
Borland编译器32位
编译0警告0错误，但在尝试运行代码时失败，您能帮忙吗
只需要一些指导，如前所述，也许我的格式很丑
只需要知道我如何才能运行此代码，缩短程序并获得相同的结果
I am using window 7 os 64 bits
a boreland compiler 32 bit
compile 0 warning 0 errors but make fail when i try to run code, can youu help
just need some guidance, as earlier suggested maybe my format is ugly
just need to know how i can get to run this code , shorten the program and have the same result
int main()
{
// start of main
//Main_menu();
}//end of main
void Main_menu(void)
{
char choice;
do
{
printf("\tA. Populate the matrix\n");
printf("\tB. Display the matrix\n");
printf("\tC. Perform operation\n");
printf("\tD. Credits\n");
printf("\tE. Exit Program\n\n\n");
printf("Please enter your choice: ");
scanf(" %c",&choice);
choice = toupper(choice);
//system("cls");
switch(choice)
{
case 'A':
{
Populate_Matrix();
break;
}
case 'B':
{
display();
break;
}
case 'C':
{
operations();
break;
}
case 'D':
{
printf("\n Dr. T. Chambers C++ group 2011\n\n\n\n");
break;
}
case 'E':
{
break;
}
default:
{
printf("Please choose a letter from A-E,You enterd a letter that is not accepted\n");
}
}
}
while(choice !=0);
}
void Populate_Matrix(void)
{
int i,j;
do
{
printf("Enter the number of matrix you need\n");
scanf("%d",&size);
}
while(size <0 || size >5);
printf("Enter the number of row and colums of mantrix\n");
scanf("%d%d",&rows,&columns);
if(size > 0 && size <= 5 )
{
printf("\tA. Add values to matrix A\n");
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
scanf("%d",&arrayA[i][j]);
}
}
}
if(size>1 && size <=5)
{
printf("\tA. Add values to matrix B\n");
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
scanf("%d",&arrayB[i][j]);
}
}
}
if(size>2 && size <=5)
{
printf("\tA. Add values to matrix C\n");
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
scanf("%d",&arrayC[i][j]);
}
}
}
}
void display(void)
{
int i, j;
if(size > 0 && size <= 5 )
{
printf("\t Add values to matrix A\n");
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
printf("%d ",arrayA[i][j]);
}
printf("\n");
}
}
printf("\n");
if(size>1 && size <=5)
{
printf("\t values to matrix B\n");
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
printf("%d ",arrayB[i][j]);
}
printf("\n");
}
}
printf("\n");
if(size>2 && size <=5)
{
printf("\tValues stores matrix C\n");
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
printf("%d ",arrayC[i][j]);
}
printf("\n");
}
}
printf("\n");
}
void operations()
{
int choice=0;
do
{
printf("\t1 Scalar\n");
printf("\t2 Addition\n");
printf("\t3 Substraction\n");
printf("\t4 Multiplication\n");
printf("\t5 Exit Program\n\n\n");
scanf(" %d",&choice);
switch(choice)
{
case 1:
ScalarMult();
break;
case 2:
addition();
break;
case 3:
subtraction();
break;
case 4:
multiplication();
break;
default:
{
printf("Please choose a letter from A-E,You enterd a letter that is not accepted\n");
}
}
}
while(choice !=0);
}
void addition()
{
int i,j;
int result[5][5]= {0};
int choice1, choice2;
printf("Enter the two matrix you need to use\n");
scanf("%d %d", &choice1,&choice2);
if(choice1 == 1 && choice2 ==2)
{
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
printf("%d ",result[i][j] = arrayA[i][j] + arrayB[i][j]);
}
printf("\n");
}
}
if(choice1 == 1 && choice2 ==3)
{
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
printf("%d ",result[i][j] = arrayA[i][j] + arrayC[i][j]);
}
printf("\n");
}
}
if(choice1 == 2 && choice2 ==3)
{
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
result[i][j] = arrayC[i][j] + arrayB[i][j];
}
}
}
}
void subtraction()
{
int i,j;
int result[5][5]= {0};
int choice1, choice2;
printf("Enter the two matrix you need to use\n");
scanf("%d %d", &choice1,&choice2);
if(choice1 == 1 && choice2 ==2)
{
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
printf("%d ",result[i][j] = arrayA[i][j] - arrayB[i][j]);
}
printf("\n");
}
}
if(choice1 == 1 && choice2 ==3)
{
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
printf("%d ",result[i][j] = arrayA[i][j] - arrayC[i][j]);
}
printf("\n");
}
}
if(choice1 == 2 && choice2 ==3)
{
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
result[i][j] = arrayC[i][j] - arrayB[i][j];
}
}
}
}
void ScalarMult()
{
int i,j;
int result[5][5]= {0};
int choice1, scaleFactor;
printf("Enter the two matrix you need to SCALE and scale factor\n");
scanf("%d %d", &choice1,&scaleFactor);
if(choice1 == 1 )
{
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
printf("%d ",arrayA[i][j] * scaleFactor);
}
printf("\n");
}
}
if(choice1 == 2 )
{
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
printf("%d ",arrayB[i][j] * scaleFactor);
}
printf("\n");
}
}
if(choice1 == 3)
{
for(i=0; i < rows; i++)
{
for(j=0; j < columns; j++)
{
printf("%d ",arrayC[i][j] * scaleFactor);
}
}
}
}
void multiplication()
const int _M1ROWS = 2;
const int _M1COLS = 3;
const int _M2ROWS = 3;
const int _M2COLS = 2;
int main()
[格式编辑]
[edit]添加了< pre>标签周围的代码，以便于阅读！ RJM [/edit]
[edited for formatting]
[edit]Added <pre> tags around code so it is readable! RJM[/edit]
推荐答案
编译0警告0错误，但在尝试运行代码时失败，您能帮忙吗?"
编号
为什么不?有两个原因:
1)您没有告诉我们问题是什么，应该做什么或做错了什么.
2)我没有看那个代码！如果您想读取代码，请对其进行格式化，以使我们易于阅读.
您想尝试哪种方法:
"compile 0 warning 0 errors but make fail when i try to run code, can youu help"
No.
Why not? For two reasons:
1) You don''t tell us what the problem is, what it is supposed to do, or what it is doing wrong.
2) I am not reading that code! If you want code to be read, then format it to make it easy for us to read.
Which would you rather try to work out:
if(size>2 && size <=5)
{
printf("\tValues stores matrix C\n");
for(i=0; i < rows; i++)
{
for(j=0;j < columns; j++)
{
printf("%d ",arrayC[i][j]);
}
printf("\n");
}
}或
if(size>2 && size <=5)
{
printf("\tValues stores matrix C\n");
for(i=0; i < rows; i++)
{
for(j=0;j < columns; j++)
{
printf("%d ",arrayC[i][j]);
}
printf("\n");
}
}
这篇关于使用Borland 32位的C ++源代码的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
查看全文
