从去年触摸60秒后StartFlipping为ViewFlipper [英] StartFlipping for ViewFlipper after 60seconds from last touch

问题描述

我的应用程序包含一个 ViewFlipper 对某些图像。应用程序启动时，在 ViewFlipper startflipping（）。当用户触摸屏幕 ViewFlipper stopflipping（）。我必须这样做，从去年接触60秒后，ViewFlipper重新开始翻转。我的类实现 onTouchListener 我有这种方法 onTouch ：

My app contains a ViewFlipper with some images. when app starts, the ViewFlipper startflipping(). When user touch the screen ViewFlipper stopflipping(). I must do that after 60 seconds from last touch, ViewFlipper to start again flipping. My class implements onTouchListener and I have this method onTouch:

public boolean onTouch(View arg0, MotionEvent arg1) {


        switch (arg1.getAction()) {
        case MotionEvent.ACTION_DOWN: {

            downXValue = arg1.getX();
            break;
        }

        case MotionEvent.ACTION_UP: {

            currentX = arg1.getX();


            if (downXValue < currentX) {
                // Set the animation
                vf.stopFlipping();
                vf.setOutAnimation(AnimationUtils.loadAnimation(this,
                        R.anim.push_right_out));
                vf.setInAnimation(AnimationUtils.loadAnimation(this,
                        R.anim.push_right_in));
                // Flip!
                vf.showPrevious();
            }


            if (downXValue > currentX) {
                // Set the animation
                vf.stopFlipping();
                vf.setOutAnimation(AnimationUtils.loadAnimation(this,
                        R.anim.push_left_out));
                vf.setInAnimation(AnimationUtils.loadAnimation(this,
                        R.anim.push_left_in));
                // Flip!
                vf.showNext();
            }

            if (downXValue == currentX) {
                final int idImage = arg0.getId();

                vf.stopFlipping();
                System.out.println("id" + idImage);
                System.out.println("last touch "+getTimeOfLastEvent());

            }
            break;
        }
        }

        // if you return false, these actions will not be recorded
        return true;
    }

和我发现这个方法，找到最后一抹时间：

and I found this method, for finding time of the last touch :

static long timeLastEvent=0;
public long getTimeOfLastEvent() {

        long duration = System.currentTimeMillis() - timeLastEvent;
        timeLastEvent = System.currentTimeMillis();
        return duration;
    }

我的问题是：我应该在哪里叫 getTimeOfLastEvent（）？如果我把它放在 onTouch（）我永远不会赶上那一刻getTimeOfLastEvent == 60000，对吧？

My question is : where should I call the getTimeOfLastEvent() ? If I put it on onTouch() I will never catch the moment when getTimeOfLastEvent==60000, right?

推荐答案

你应该做的就是创建一个 处理程序 （应该是你的活动的实例变量并应在的onCreate ）

What you should do is create a Handler (should be an instance variable of your Activity and should be initialized during onCreate):

Handler myHandler = new Handler();

此外，你需要一个的Runnable ，可以重新开始翻转（还需要你的活动中声明 ）：

Also you will need a Runnable that can start the flipping again (also needs to be declared within your Activity):

private Runnable flipController = new Runnable() {
  @Override
  public void run() {
    vf.startFlipping();
  }
};

然后在你的的onClick 您刚刚发布的Runnable 在处理程序但延迟60秒钟：

Then in your onClick you just post the Runnable on the Handler but delayed by 60 seconds:

myHandler.postDelayed( flipController, 60000 );

张贴延迟手段：快跑60秒这个code

Posting it delayed means: "Run this code in 60 seconds".

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