如何增加一天的额外时间 [英] how to add an extra day to hour

问题描述

你好朋友我有这个问题

hello frens i have this problem

DateTime arrtime = DateTime.Parse(txtarrivaltime.Text);
DateTime endTime = DateTime.Now;

TimeSpan span1 = endTime.Subtract(arrtime);
TimeSpan span2 = span1.Duration();

string NumOfDays = span1.Days;


string Shours = span2.Hours.ToString()+ ?;

现在我要动态增加小时数，即24 *一些值，例如24 * 1或24 * 2或...如果NumOfDays大于0，则以小时为单位.
请提供代码

now i want to dynamically add hours i.e. 24* some value like 24*1 or 24*2 or ... in Shours if the NumOfDays is more than 0. how can i do this dynamically?
please provide with the code

推荐答案

使用以下内容:

Use the following :

// add 1 day to the current date time
DateTime dt = DateTime.Now.AddDays(1);

稍微转一下-做ToString最后，不要在字符串中存储要用于算术的任何内容:

Turn it round a little - do the ToString last, and don''t store anything you want to use for arithmetic in a string:

DateTime arrtime = DateTime.Parse("txtarrivaltime.Text");
DateTime endTime = DateTime.Now;

TimeSpan span1 = endTime.Subtract(arrtime);
TimeSpan span2 = span1.Duration();

int NumOfDays = span1.Days;

TimeSpan span3 = new TimeSpan(24 * NumOfDays, 0, 0);
TimeSpan span4 = span2.Add(span3);
string Shours = span4.TotalHours.ToString();

(这是故意散布的，因此您可以更好地看到步骤)

(This is deliberately spread out, so you can see the steps better)

如果我正确理解了您的问题，您不能只添加span1.Days*24吗?

在任何情况下span1.Days可能为负吗?如果是这样，请使用+ span1.Days > 0 ? span1.Days * 24.0 : 0.0;

If I undedrstand your question correctly, can''t you just add span1.Days*24?

Is there any case where span1.Days might be negative? If so, then use + span1.Days > 0 ? span1.Days * 24.0 : 0.0;

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