双随机数和数组 [英] double random number and array
本文介绍了双随机数和数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是整数中的随机代码gen,对吧?
this is the code random gen in integer, right?
Random random = new Random();
int irandom = random.Next(1, 100);
随机生成的双倍数又如何呢?
从0.0到100.0
what about for random gen in double?
from 0.0 to 100.0
and how make an array (25 to 50) random numbers?
推荐答案
您可以使用NextDouble
或Sample
并将其添加到随机整数中.
参考: http://msdn.microsoft.com/en-us/library/system. random.nextdouble.aspx [ ^ ]
您可以生成n个随机数,并将其放入数组或任何其他形式.尝试一下.
You can useNextDouble
orSample
and add it to your random integer.
Ref: http://msdn.microsoft.com/en-us/library/system.random.nextdouble.aspx[^]
You can generate n number of randoms and put it in array or whatever. Try it.
引用该线程
http://stackoverflow.com/questions/609501/generating-a-random-小数的c锐度 [ ^ ]
Refer this thread
http://stackoverflow.com/questions/609501/generating-a-random-decimal-in-c-sharp[^]
获取0到1000之间的随机数,然后将其映射到0到100以获取1到100之间的随机数(带小数点)点精度.
get a random number between 0 and 1000 and then map it to 0 to 100 to get a random number between 1 and 100 with one decimal point precision.
public static double getrand()
{
Random random = new Random();
return random.Next(0, 1000)/10.0;
}
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