GridView中的FileUpload问题 [英] Problem with FileUpload in gridview

问题描述

亲爱的所有人，

请帮助我如何从Gridview中的PostedFile中读取流，但是HasFile属性在GridView ASP:FileUpload控件中为true.已通过此文件找到FileUpload

Dear All,

Please, Help how can I read stream from the PostedFile in Gridview However HasFile property is true in GridView ASP:FileUpload control. FileUpload has been found through this

FileUpload FileUpload1 = (FileUpload)row.Cells[0].FindControl("FileUpload1");

并使用此代码段将数据保存到数据库中，但执行 FileUpload1.PostedFile.InputStream.Read(pic，0，len)后， byte [] pic 中的所有零(0)值; 这句话.

and Used this snippet to save the data in Database but byte[] pic has all zero (0) values in it after execute FileUpload1.PostedFile.InputStream.Read(pic, 0, len); this statement.

if(FileUpload1.HasFile)
{
      int len = FileUpload1.PostedFile.ContentLength;
      byte[] pic = new byte[len];
      FileUpload1.PostedFile.InputStream.Read(pic, 0, len);      
}

解决方案是什么?....将数据加载到byte []图片中，但是此代码段在Gridview之外运行良好.

what would be the solution?.... to load data in byte[] pic however this snippet is working fine out side the Gridview.

推荐答案

尝试一下，

Try this,

if (FileUpload1.HasFile)
  {
    string contentType = FileUpload1.PostedFile.ContentType;

    // Get the bytes from the uploaded file
    byte[] fileData = new byte[FileUpload1.PostedFile.InputStream.Length];
    FileUpload1.PostedFile.InputStream.Read(fileData, 0, fileData.Length);
}

我的解决方案.....


我必须通过流媒体来工作...
首先添加..

My Solution.....


I have to work by Streaming...
first of all add..

System.IO

在RowCommand的gridview中

上传文件...

in the gridview on RowCommand

Upload Document...

FileUpload1.PostedFile.InputStream.Seek(0, SeekOrigin.Begin);
Stream fs = FileUpload1.PostedFile.InputStream;
BinaryReader br = new BinaryReader(fs);
Byte[] bytes = br.ReadBytes((Int32)fs.Length);

// Allocate your data to DB nVarBinary field.
oelScanImages.ImageFile = bytes;

 br.Close();
 fs.Close();

感谢所有参与协助我的人.

Thanks to all who participate to assist me.

您好，
试试这个...

Hi,
Try this...

Byte[] imgByte = null;
try
{
   if (FileUpload1.HasFile && FileUpload1.PostedFile != null)
   {
      //To create a PostedFile
      HttpPostedFile File = FileUpload1.PostedFile;
      //Create byte Array with file len
      imgByte = new Byte[File.ContentLength];
      //force the control to load data in array
      File.InputStream.Read(imgByte, 0, File.ContentLength);
      originalSize = File.ContentLength;
   }
 }
 catch
 {

 }

如果有帮助，请投票作为答案...

问候，

代数

Please vote as answer if help...

Regards,

Algem

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