C ++程序从当前系统扣除5分钟 [英] c++ program to deduct 5 minute from the current system

问题描述

我正在尝试编写一个程序，该程序必须从当前系统中扣除5分钟.如何在vc ++中实现这一目标...

问候，
sanath

I am trying to write a program that has to perform deduction of 5 minute from current system. How this can be achieved in vc++...

regards,
sanath

推荐答案

DateTime ^ dt;
dt = DateTime::Now.AddMinutes(-5);
Console::WriteLine(L"5 minutes ago : {0}", dt);

#include< stdio.h>
#include< iostream.h>
#include< time.h>
#include< conio.h>

int main()
{

time_t rawtime;
struct tm * timeinfo;
int min，hr，sec;

时间(& rawtime);
timeinfo =当地时间(& rawtime);

printf(当前本地时间和日期:％s"，asctime(timeinfo))；
min = timeinfo-> tm_min;
hr = timeinfo-> tm_hour;
//sec = timeinfo-> tm_sec;


min = min-5;

if(min< 0)
{
min = min + 60;
hr--;
cout<"\ n减去5分钟后，新时间为"<< hr<:"<< min;
}
其他
{
cout<"\ n减去5分钟后，新时间为"<< hr<:"<< min;

}

getch();
返回0;

}

这是完整的代码

#include <stdio.h>
#include<iostream.h>
#include <time.h>
#include<conio.h>

int main ()
{

time_t rawtime;
struct tm * timeinfo;
int min, hr,sec;

time ( &rawtime );
timeinfo = localtime ( &rawtime );

printf ( "Current local time and date: %s", asctime (timeinfo) );
min=timeinfo->tm_min;
hr=timeinfo->tm_hour;
// sec=timeinfo->tm_sec;


min=min-5;

if(min<0)
{
min=min+60;
hr--;
cout<<"\n After deducting 5 min new time is "<<hr<<":"<<min;
}
else
{
cout<<"\n After deducting 5 min new time is "<<hr<<":"<<min;

}

getch();
return 0;

}

this is complete code

在c ++中，您可以通过__TIME__检索系统时间，并且可以将此时间存储在变量中

in c++ you can retrieve system time by __TIME__ and you can store this time in a variable

char code my_time[] = "Compile Time = " __TIME__;

现在您可以获取值并执行您想做的事情

祝你好运.

now you can get the values and do what you want to do

best of luck for the rest.

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