Gridview中的模板字段 [英] Template field in Gridview

问题描述

大家好，

如何在模板字段GridView，Asp.Net中检查2个条件.取决于应在gridview中显示图像按钮

帮助pl

问候，
Praveen

Hello all,

How to check 2 conditions in the template field, GridView, Asp.Net. Depending upon that the image button should be displayed in the gridview

Help pl

Regards,
Praveen

推荐答案

U可以在gridview中使用RowDataBound事件
尝试n了解以下示例:


受保护的void gv1_RowDataBound(object sender，GridViewRowEventArgs e)
{
试试
{
如果(e.Row.RowType == DataControlRowType.DataRow)
{
字符串状态= DataBinder.Eval(e.Row.DataItem，"Status").ToString();
如果(status.Trim()==显示")
{
((LinkLink)e.Row.FindControl("lbtnView")).Visible = true;
((LinkLink)e.Row.FindControl("lbtnClose")).Visible = true;

}
否则，如果(status.Trim()=="Close")
{
((LinkLink)e.Row.FindControl("lbtnView")).Visible = true;
((LinkBut​​ton)e.Row.FindControl("lbtnClose")).Visible = false;
lblRemarks.Visible = true;
labelRemark.Visible = true;
}

}
}

U can use RowDataBound Event in gridview
Try n Understand the following example:


protected void gv1_RowDataBound(object sender, GridViewRowEventArgs e)
{
try
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
string status = DataBinder.Eval(e.Row.DataItem, "Status").ToString();
if (status.Trim() == "Show")
{
((LinkButton)e.Row.FindControl("lbtnView")).Visible = true;
((LinkButton)e.Row.FindControl("lbtnClose")).Visible = true;

}
else if (status.Trim() == "Close")
{
((LinkButton)e.Row.FindControl("lbtnView")).Visible = true;
((LinkButton)e.Row.FindControl("lbtnClose")).Visible = false;
lblRemarks.Visible = true;
labelRemark.Visible = true;
}

}
}

，您可以使用行数据绑定在gridview中显示图像按钮.
如果您要针对您要检查的内容专门发布一些相关代码.

you can use row databound for displaying the image button in gridview.
if you want specific post some relevant code against what you want to check..

http://www.dotnetfunda.com/tutorials/controls/gridview.aspx


请检查此链接....很遗憾，您可以解决您的问题..

http://www.dotnetfunda.com/tutorials/controls/gridview.aspx


Please check this link....unfortunality you can get solution of your questation..

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