使用参数打开表格 [英] Open Form with Parameters

问题描述

我有一个DLL文件(myForms.DLL)文件，其中包含一个表单(form1)，
显示重载，并带有一个这样的参数:

公共重载子节目(ByVal数据作为dataTable)
......
结束Sub


而且，我有一个没有DLL参考的EXE项目，我想打开EXE项目中myForms.DLL中存在的form1.我加载了myForms.DLL程序集，并得到了像这样的form1:
.....
.....
以窗体= CType(Activator.CreateInstance(typ)，Form)的形式暗化f

现在，我想显示带有参数的表格:

将mydata调暗为新的datatabe
f.show(mydata)

我的问题是，表单无法识别Parameter或Overloads Show()并始终显示原始表单.如何使用参数打开此表单?

thanx

i have a DLL file (myForms.DLL) file which contains one form (form1),
with overloads show, with one parameter like this:

Public Overloads Sub Show(ByVal Data As dataTable)
......
end Sub


and, i have an EXE Project without reference for DLL, i want to open the form1 which exist in myForms.DLL in EXE Project. I loaded the myForms.DLL assembley and get the form1 like this:
.....
.....
dim f as form = CType(Activator.CreateInstance(typ), Form)

now, i want to show the form with parameter:

dim mydata as new datatabe
f.show(mydata)

my problem is, the form can not identify the Parameter or Overloads Show() and always Show the original form. How can i open this form with parameter?

thanx

推荐答案

将表单创建为表单类型，而不是Form.由于Form对您重载的Show方法一无所知，因此将无法正常工作.

Create the form as your form type, not Form. Since Form knows nothing of your overloaded Show method, it''s not going to work.

Dim f as MyForm = CType(Activator.CreateInstance(typ), MyForm)

戴夫，

我知道，但是我不能使用表单类型，因为我没有DLL的引用.

我使用type和getAssembly从DLL文件中提取了表单对象.

hi Dave,

i know that but i can not use form type coz i have no reference for the DLL.

i extracted the form object from DLL file using type and getAssembly.

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