什么是地址偏移 [英] what is address offset

问题描述

我的代码是:

my code is :

x = x & 0xffff
x << 8

我不知道0xffff是地址偏移量还是十六进制数.

I don''t know whether 0xffff is an address offset or hex number.

推荐答案

前缀``0x''表示十六进制数.它是指地址还是其他数量，完全取决于您的代码，因为它只是一种表示方式.

The prefix ''0x'' indicates a hexadecimal number. Whether it refers to an address or any other quantity entirely depends on your code as it''s only a way of representation.

int number_of_apples = 0x13;                        /* 19 apples */
short int number_of_fields_on_checker_board = 0100; /* octal number for 64 */
void* pointer_to_nowhere = 546233512;               /* points to the address 546233512 */

它只是十六进制值(65535).

It is just a value (65535) in Hex.

偏移量用于避免重复.
在您的情况下，为避免地址重复，对于x的每个值，十六进制值都应为"AND" ed.
这样就不会有重复的机会.
但是我不知道您使用的是这么大的十六进制数字.

offset is used to avoid the duplicate.
In your case, to avoid the duplicate of the address, for each value of x the hexa decimal value is ''AND'' ed.
so that there is not chance of duplicating.
But i wonder y such a big hexa number you are using.

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