无退货功能 [英] No Return On Function

问题描述

我有一个未签名的char * data，它提供了以下内容的输出....

I have an unsigned char *data that gives me the output of the following....

-------------IP Data Begins-------------
HTTP/1.1 200 OKP3P: policyref="http://g
oogleads.g.doubleclick.net/pagead/gcn_p3p_.xml"
, CP="CURa ADMa DEVa TAIo PSAo PSDo OUR IND UNI
PUR INT DEM STA PRE COM NAV OTC NOI DSP COR"
Content-Type: text/html; charset=UTF-8
X-Content-Type-Options: nosniffContent-
Encoding: gipDate: Mon, 29 Aug 201
1 21:19:36 GMTServer: cafeCache
-Control: privateContent-Length: 4863
X-XSS-Protection: 1; mode=block

该代码未返回正确的输出...它始终为0.我确定它与未签名的char * data有关.

This code isn''t returning the correct output...it''s always 0. I''m sure it has something to do with the unsigned char *data.

int mycount;
char myints[] = {reinterpret_cast<char>(data)};
mycount = (int) count (myints, reinterpret_cast<char>(data), 'HTTP');
cout << "HTTP Appears " << mycount << " times.\n";
return;</char></char>

推荐答案

您的计数函数可能是错误的.尝试这样的方法(警告，未编译的代码！):

Your count function is probably wrong. Try something like this instead (Warning, uncompiled code ahead!):

/// returns the number of times element appears in str.
int count( const std::string& str, const char* element )
{
    int count = 0;
    for( size_t last = -1; 
         ( last = str.find( element, last + 1 ) ) != std::string::npos; 
         ++count );
    return count;
}

int mycount = count( data, "HTTP" );

看看标准字符串库 [

Take a look at the standard strings library[^].

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