帮助:将gabor formola转换为C族语言 [英] Help:convert gabor formola to C family Language

问题描述

嗨 任何人都可以将gabor公式转换为C#中的代码吗?
以下页面解释了该公式:
Gabor过滤器

Hi Can anybody convert gabor formula to code in C#
the following Page explain the formula:
Gabor filter

推荐答案

我相信这就是你的身份之后.

公平警告:

-我还没有运行代码
-在阅读此问题之前，我什至从未听说过MATLAB

I believe this is what you are after.

FAIR WARNING:

- i haven''t run thus code
- i had never even heard of MATLAB before reading this question

public IDictionary<Point, double> gaborFn(double sigma, double theta, double lambda, double psi, double gamma)
{
    IDictionary<Point,double> result = new Dictionary<Point,double> ();

    double sigma_x = sigma;
    double sigma_y = sigma/gamma;

    //Bounding box
    int nstds = 3;
    double xmax = Math.Max(Math.Abs(nstds*sigma_x*Math.Cos(theta)),Math.Abs(nstds*sigma_y*Math.Sin(theta)));
    xmax = Math.Ceiling(Math.Max(1,xmax));
    double ymax = Math.Max(Math.Abs(nstds*sigma_x*Math.Sin(theta)),Math.Abs(nstds*sigma_y*Math.Cos(theta)));
    ymax = Math.Ceiling(Math.Max(1,ymax));
    double xmin = -xmax;
    double ymin = -ymax;

    for (int x = (int)xmin; x <=xmax;x++)
    {
        for (int y = (int)ymin; x <= ymax; x++)
        {

            // Rotation
            double x_theta = x * Math.Cos(theta) + y * Math.Sin(theta);
            double y_theta = -x * Math.Sin(theta) + y * Math.Cos(theta);

            double gb = 1 / (2 * Math.PI * sigma_x * sigma_y) * Math.Exp(-.5 * (Math.Pow(x_theta, 2) / Math.Pow(sigma_x, 2) + Math.Pow(y_theta, 2) / Math.Pow(sigma_y, 2))) * Math.Cos(2 * Math.PI / lambda * x_theta + psi);

            result.Add(new Point(x, y), gb);

        }
    }



    return result;
}

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