在asp.net中填充模态窗口 [英] Populating a Modal window in asp.net

问题描述

我有一个Datagrid，每列都有一个链接按钮.单击链接按钮时，将显示模态"弹出窗口.我想让模态"窗口在打开时从父"页面显示详细信息".任何人都可以建议如何做到这一点.在此先感谢

Hi I have a Datagrid with a link button for each column. When clicked the link button displays a Modal popup window. I want to get the Modal window to display Details from the Parent page when opened. Can anyone suggest how to do this. Thanks in advance

推荐答案

This[^] might help you.

受保护的void GridView1_RowCommand(对象发送者，GridViewCommandEventArgs e)
{

url ="ReportSwitch.aspx?Level =" + rdoEducationLevel1.SelectedItem.Text.ToString()+& ListItem =" + ASPxListBox1.SelectedItem.Text.ToString().Trim()+";
ScriptManager.RegisterStartupScript(this，this.GetType()，"PopUpWindow"，"PopUpWindow(""+ url +"'');，true);

}

在JavaScript中使用此代码:



函数PopUpWindow(url){

window.open(URL，"Report"，``高度= 500，宽度= 1050，左侧= 30，顶部= 50，可调整大小=否，滚动条=是，工具栏=否，状态=否，位置=否'')
}

protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{

url = "ReportSwitch.aspx?Level=" + rdoEducationLevel1.SelectedItem.Text.ToString() + "&ListItem=" + ASPxListBox1.SelectedItem.Text.ToString().Trim() + "";
ScriptManager.RegisterStartupScript(this, this.GetType(), "PopUpWindow", "PopUpWindow(''" + url + "'');", true);

}

in JavaScript Use this Code:



function PopUpWindow(url) {

window.open(url, "Report", ''height=500,width=1050,left=30,top=50,resizable=no,scrollbars=yes,toolbar=no,status=no,location=no'')
}

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