错误2664无法将Int转换为LPDWORD [英] Error 2664 CannotConvert Int To LPDWORD

问题描述

我在这条线上出现错误...

I''m getting an error on this line...

if (WSAIoctl(sniffer, SIO_RCVALL, &j, sizeof(j), 0, 0, &in, 0, 0) == SOCKET_ERROR)
{

the &in is in red squiggles.

推荐答案

以下是使用WSAIoctl

Here is a good example using WSAIoctl Sniffing using Winsock[^]

Best regards
Espen Harlinn

这是因为DWORD 是unsigned long，而不是int.当直接将DWORD 设置为int 时，编译器将让您离开(通过执行隐式对偶运算)，但是它不能对指针执行相同的操作，因此您要么必须将其显式转换为(错误，因为您不能保证它们的大小相同)，或者即使实际将int复制到临时DWORD中，也要传递指向实际DWORD的指针.

It''s because a DWORD is an unsigned long, not an int. The compiler will let you off when directly setting a DWORD to an int (by doing an implicit convesion) but it can''t do the same for a pointer, so your either going to have to explicitly cast to LPDWORD (Bad, since your''e not guaranteed that they will be the same size) Or pass a pointer to an actual DWORD, even if you just copy your int into a temporary DWORD.

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