两人指挥游戏 [英] Two Player Command Game

问题描述

大家好，

我正在制作的Java游戏出现问题.这是飞镖游戏，但是要扔"飞镖，必须输入命令.我设法创建了一种投掷" 3支飞镖的方法，从501中扣除了3支飞镖的最终得分.这是在我的Darts类的"playGame"部分完成的.

我希望能够从已经完成的比赛中制作转弯系统，并且也可以为2个玩家建立转弯系统.谢谢！

这是我的代码:

Hey guys,

I''m having a problem with my java game I am making. It is a darts game, but to "throw" a dart, you must enter a command. I''ve managed to create a way to "throw" 3 darts, with the final score of the 3 darts deducted from 501. This is done in the "playGame" part of my Darts class.

I want to be able to make a turn system from what I have made already, and a way too make it for 2 players. Thanks!

Here is my code:

public class Darts{
	
	int userInput;
	
	public static void main(String[] args) {
		
		
		menu();
		
	}
	public static void menu (){
		int userInput;
		
		TextIO.putln("Darts!");
		TextIO.putln();
		TextIO.putln();
		TextIO.putln("Please select an Option :");
		TextIO.putln("1 - to Play the Game");
		TextIO.putln("2 - for Instructions");
		TextIO.putln("3 - to Exit the Game");  
		
		userInput = TextIO.getlnInt();
		
		switch (userInput){
		case 1 : playGame();
		case 2 : instructions();		
		case 3 : endGame();		
		default : NotA();
		}
}
	
	public static void playGame() {
		char anyChar;
		Turn currentTurn = new Turn();
		currentTurn.thrown[0] = new Throw();
		TextIO.putln("What number are you aiming at?");
		currentTurn.thrown[0].number = TextIO.getlnInt();
		TextIO.putln("Enter 2 for a Double, 3 for a Treble, otherwise enter 1:");
		currentTurn.thrown[0].multiplier = TextIO.getlnInt();
		TextIO.put("You scored: ");
		TextIO.putln(currentTurn.thrown[0].number * currentTurn.thrown[0].multiplier);
		currentTurn.thrown[1] = new Throw();
		TextIO.putln("What number are you aiming at?");
		currentTurn.thrown[1].number = TextIO.getlnInt();
		TextIO.putln("Enter 2 for a Double, 3 for a Treble, otherwise enter 1:");
		currentTurn.thrown[1].multiplier = TextIO.getlnInt();
		TextIO.put("You scored: ");
		TextIO.putln(currentTurn.thrown[1].number * currentTurn.thrown[1].multiplier);
		currentTurn.thrown[2] = new Throw();
		TextIO.putln("What number are you aiming at?");
		currentTurn.thrown[2].number = TextIO.getlnInt(); 
		TextIO.putln("Enter 2 for a Double, 3 for a Treble, otherwise enter 1:");
		currentTurn.thrown[2].multiplier = TextIO.getlnInt();
		TextIO.put("You scored: ");
		TextIO.putln(currentTurn.thrown[2].number * currentTurn.thrown[2].multiplier);
		TextIO.put("Your score now is: ");
		TextIO.putln(currentTurn.sTotal - ((currentTurn.thrown[0].number * currentTurn.thrown[0].multiplier) + (currentTurn.thrown[1].number * currentTurn.thrown[1].multiplier) + (currentTurn.thrown[2].number * currentTurn.thrown[2].multiplier)));
		
		int nTotal = currentTurn.sTotal - ((currentTurn.thrown[0].number * currentTurn.thrown[0].multiplier) + (currentTurn.thrown[1].number * currentTurn.thrown[1].multiplier) + (currentTurn.thrown[2].number * currentTurn.thrown[2].multiplier));

		
		anyChar = TextIO.getAnyChar();
		menu();
		
	}
	

public static void instructions() {
	char anyChar;
	
	TextIO.putln();
	TextIO.putln("Commands");
	TextIO.putln();
	TextIO.putln("You have three darts, when prompted you need to enter your command.");
	TextIO.putln("Your command will be a number followed by a number.");
	TextIO.putln("The numbers will be 1, 2 and 3.");
	TextIO.putln("");
	TextIO.putln("They represent Single, Double or Triple");
	TextIO.putln("E.g. 20 followed by 2 represents Double twenty.");
	TextIO.putln();
	TextIO.put("Press any key to continue: ");
	anyChar = TextIO.getAnyChar();
	
	menu();
	
	}
public static void endGame() {
	
	System.exit(0);
	}

public static void NotA() {
	menu();
	}
}

那是我的主菜单，第一轮转向系统.这是我使用的其他类:

That was my main menu, with the system of taking the first turn. Here are the other classes I use:

public class Turn {
	
	Throw[] thrown = new Throw[3];  // three darts thrown per turn
	int sTotal = 501;    
}

public class Throw {
	
	  int number;
	  int multiplier; // 3 for a treble, 2 for a double, 1 for anything else

}

推荐答案

您需要考虑一下在现实世界中飞镖比赛的运行​​方式:
playGame()函数一直运行到一名玩家降至零.每个玩家轮流进行掷球，总共有3球.每次掷球之后，检查分数以查看游戏是否结束.重复.
所以playGame()应该看起来像:

You need to think about how a darts match runs in the real world:
The playGame() function runs until one player gets down to zero. Each player takes it in turns to throw, and has a total of 3 throws. After each throw the score is checked to see if the game has ended. Repeat.
So playGame() should look something like:

while not finished
    for darts = 1 to 3
        score = player1.throw()
        if score == 0
            finished = true
            break;
    if finished
        break;
// repeat the above for player 2

// repeat the entire process

这篇关于两人指挥游戏的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！