休眠查询以获取表中特定列的逗号分隔值 [英] Hibernate Query to get the comma seperated values of a particular column in a table

问题描述

下午好

我的疑问是我的数据库中有一个名为userinfo的表，其中一列为SenderId.现在我想使用逗号分隔符将SenderId列的所有值转换为字符串类型的数组.请告诉我如何编写对此进行休眠查询.

在此先感谢

Hi Good Afternoon

My doubt is i have a table called userinfo in my database with one of the column as SenderId.Now i want to get all the values of the SenderId column into a string type array using comma seperator.Can you please tell me how to write the hibernate query for this.

Thanks in advance

推荐答案

您好，

http ://blog.sqlauthority.com/2008/06/04/sql-server-create-a-comma-delimited-list-using-select-clause-from-table-column/ [ ^ ]

按照上面的链接.希望对您有帮助.

谢谢
sanjeev

Hello,

http://blog.sqlauthority.com/2008/06/04/sql-server-create-a-comma-delimited-list-using-select-clause-from-table-column/[^]

follow above link. hoping it will help you out.

thanks
sanjeev

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