菜单项可见性 [英] menu item visibility

问题描述

大家好！

我创建了form1，在其中我创建了菜单栏名称"Function"并具有子菜单
"F1"，"F2"，"F3"，"F4"，默认情况下，其可见性为false，修饰符为public

我用相同的名称创建了一个函数pce private void display()
然后在那边制作
F1.visibile = true
F2.visibile = true
F3.visibile = true
F4.visibile = true

但这些子菜单仍然不可见
为什么

我不明白我在做什么小错误

您能帮我吗?

Hi to all!

i have create form1 in which i created menustrip names "Function" and have submenus
"F1", "F2", "F3", "F4", default i their visibility is false and modifiers is public

and i create one function in the same namespce private void display()
and over there i make the
F1.visibile=true
F2.visibile=true
F3.visibile=true
F4.visibile=true

but still these submenus are not visible
why

i didnt understand that what little mistake i am doing

can u help me please

推荐答案

1. F1是否真的与菜单中使用的F1对象相同?
如果是另一个
创建的相同对象 Menu = new CustomizedSubMenu( ... );菜单已经存在时，则其可见性更改将不会对原始F1对象产生影响.

2.确保F1的父母也是visilbe = true

1. Is F1 really the same F1 object that is used in the menu?
If it''s another, identical object created with
Menu = new CustomizedSubMenu( ... ); at a time when the menu already exists, then its visibility change will have no effect on the original F1 object.

2. Make sure that F1''s parent is also visilbe = true

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