C#WPF可以解决此代码吗? [英] C# WPF can some one fix this code?

问题描述

这是我的代码

this is my code

public partial class MainWindow : Window
   {
       private Storyboard myStoryboard;
       private Storyboard myStoryboard2;
       public MainWindow()
       {
           InitializeComponent();
           //animation for the hide
           ThicknessAnimation myDoubleAnimation = new ThicknessAnimation();
           myDoubleAnimation.From = (textBlock3.Margin = new Thickness(378, 0, 0, 0));
           myDoubleAnimation.From = (SV.Margin = new Thickness(413, 0, 0, 0));
           myDoubleAnimation.To = (textBlock3.Margin = new Thickness(28, 0, 0, 0));
           myDoubleAnimation.To = (SV.Margin = new Thickness(35, 0, 0, 0));
           myDoubleAnimation.Duration = new Duration(TimeSpan.FromSeconds(0.5));
           myStoryboard = new Storyboard();
           myStoryboard.Children.Add(myDoubleAnimation);
           Storyboard.SetTargetName(myDoubleAnimation, textBlock3.Name);
           Storyboard.SetTargetProperty(myDoubleAnimation, new PropertyPath(Rectangle.MarginProperty));
           //animation for the show
           ThicknessAnimation myDoubleAnimation2 = new ThicknessAnimation();
           myDoubleAnimation2.From = (Margin = new Thickness(28, 0, 0, 0));
           myDoubleAnimation2.To = (Margin = new Thickness(378, 0, 0, 0));
           myDoubleAnimation2.Duration = new Duration(TimeSpan.FromSeconds(0.5));
           myStoryboard2 = new Storyboard();
           myStoryboard2.Children.Add(myDoubleAnimation2);
           Storyboard.SetTargetName(myDoubleAnimation2, textBlock3.Name);
           Storyboard.SetTargetProperty(myDoubleAnimation2, new PropertyPath(Rectangle.MarginProperty));

       }

现在我只希望同时播放2个动画，但是使用此代码，一切都不会动

now i just want 2 animations going at the same time, but with i do this code, nothing moves

推荐答案

不，它不会.我不知道您是否可以一次运行两个情节提要，或者是否需要将它们放在同一情节提要中.我知道您需要启动它.

此处 [ ^ ]

No, it won''t. I a, not sure if you can run two storyboards at once, or if they need to be in the same storyboard. I do know you need to start it.

Here[^]

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