XPath错误消息(数据类型) [英] XPath error message (data types)

问题描述

你好，

我不明白为什么我会从XPath中收到以下错误:

Hello,

I do not understand why I get the following error from XPath:

1.
   <xsl:choose>
           <xsl:when test="$rownr = 0">
                   <xsl:attribute name="FontSize" select=" '24 px' "/>
                   <xsl:attribute name="Foreground" select=" 'MidnightBlue' "/>
           </xsl:when>
   </xsl:choose>

   <!-- Warning: Required item type of first operand of '=' is numeric; supplied value has item type xs:string -->

我从中了解到的是，应该为变量$ rownr赋予一个数值作为正确的操作数.我不明白，因为$ rownr是未定义的类型(我认为)并且正确的操作数已经是数字，即0而不是``0''(我认为).

如何解决此问题以及代码中的实际情况?
我正在使用EditX Xml Editor免费版本.

谢谢

//我通过编写此代码修复了该问题:
< xsl:param name ="rownr"> 0</xsl:param>

我不知道为什么用这种方法解决了错误.
有人可以告诉我吗?

谢谢

All I understand from it, is that the variable $rownr is supposed to be given a numeric value as right operand. I do not understand that, because $rownr is of an undefined type (I think) and the right operand is already numeric, i.e. 0 and not ''0'' (I think).

How do I fix this and what is really going on in my code?
I am using EditX Xml Editor free version.

Thank you

// I have fixed it by writing this:
<xsl:param name="rownr">0</xsl:param>

I do not know why the error was fixed this way.
Can someone please tell me?

Thank you

推荐答案

rownr = 0" < xsl:attribute 名称 =" 选择 ' 24 px'" > < xsl:attribute 名称 =" 选择 ' MidnightBlue'" > < /xsl:何时 > < /xsl:choose > <！- 警告:"="的第一个操作数的必需项类型'是数字；提供的值的项目类型为xs:string ->

rownr = 0"> <xsl:attribute name="FontSize" select=" '24 px' "/> <xsl:attribute name="Foreground" select=" 'MidnightBlue' "/> </xsl:when> </xsl:choose> <!-- Warning: Required item type of first operand of '=' is numeric; supplied value has item type xs:string -->

我从中了解到的是，应该给变量

All I understand from it, is that the variable

rownr一个数值作为正确的操作数.我不明白，因为

rownr is supposed to be given a numeric value as right operand. I do not understand that, because

rownr是未定义的类型(我认为)，并且正确的操作数已经是数字，即0而不是"0"(我认为).

如何解决此问题以及代码中的实际情况?
我正在使用EditX Xml Editor免费版本.

谢谢

//我通过编写此代码修复了该问题:
< xsl:param name ="rownr"> 0</xsl:param>

我不知道为什么用这种方法解决了错误.
有人可以告诉我吗?

谢谢

rownr is of an undefined type (I think) and the right operand is already numeric, i.e. 0 and not ''0'' (I think).

How do I fix this and what is really going on in my code?
I am using EditX Xml Editor free version.

Thank you

// I have fixed it by writing this:
<xsl:param name="rownr">0</xsl:param>

I do not know why the error was fixed this way.
Can someone please tell me?

Thank you

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