在C#中的自定义位置上显示StartMenu [英] Show StartMenu on custom position in C#

问题描述

大家好.

我有一个小问题.我想在自定义位置上显示win7的开始菜单，但我的代码没有执行任何操作.

Hi together.

I have a little problem. I want to show the startmenu of win7 on a custom position but my code did nothing.

<pre lang="cs">IntPtr StartMenu = FindWindow("DV2ControlHost", null);<br />
MoveWindow(StartMenu, x, y, width, height, true);<br />
ShowWindowAsync(StartMenu, 1);</pre><br />

推荐答案

您为什么认为它应该显示开始"菜单?

您可以使用P/Invoked Windows API SendInput轻松模拟Ctrl + Esc(通常显示此菜单)，请参见System.Diagnostic.Process.Start完成，请参见 http://msdn.microsoft.com/en-us/library/system.diagnostics.process.aspx [

Why do you think it should show the Start Menu?

You can easily simulate Ctrl+Esc (which normally shows this menu) by using P/Invoked Windows API SendInput, see http://msdn.microsoft.com/en-us/library/ms646310(v=vs.85).aspx[^].

However I would not recommend doing anything about Start Menu at all. A good user will feel abused. The user know when and why using Start menu. What''s the purpose of it? If you need to start something, this is done via System.Diagnostic.Process.Start, see http://msdn.microsoft.com/en-us/library/system.diagnostics.process.aspx[^].

—SA

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