用户定义数据类型到char *的转换. [英] userdefine datatype to char* conversion.

问题描述

你好，

我有一个从QString类派生的类，我想将typecast myString重载为char *转换.我做了如下.

Hello,

I have make a class derived from QString class and i want to overload typecast myString to char* conversion. i did as following.

// mystring.h
#ifndef MYSTRING_H
#define MYSTRING_H

#include <QString>

class MyString : public QString
{
public:
    MyString();
    operator char*()
    {
        QByteArray ba = toLocal8Bit();
        return ba.data();
    }
    void operator =(const QString& str){ clear();append(str);}
};

#endif // MYSTRING_H


// main.cpp file

#include <mystring.h>
int main(int argv,char* argc[])
{
   char* strChar = NULL;
   MyString strMy;
   strMy = "Hello";
   strChar = strMy;
   int i = 0;
}

但我在strChar中无法获得"Hello".
如何重载char *运算符?
我无法弄清楚我的代码出了什么问题.


预先感谢.

but i can''t get "Hello" in strChar.
How do i overload operator char* ?
I can''t get whats wrong in my code.


Thanks in advance.

推荐答案

您将返回由临时对象保存的缓冲区.

You are returning the buffer held by a temporary object.

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