如何使用Java代码中的参数执行JAR文件? [英] How to execute JAR file with arguments from Java Code?

问题描述

我有以下命令:

java -jar trang.jar 5-something.xml 5.1-somethingElse.xsd

我想从Java程序执行此操作.

I have this command:

java -jar trang.jar 5-something.xml 5.1-somethingElse.xsd

I would like to execute this from Java program.

Desktop.getDesktop().open(new File("trang.jar"));

这行执行程序mas，而没有参数是无用的.

This line executes the program mas without the arguments is useless. There''s any way to do what I need?

推荐答案

最简单的方法是使用Runtime.exec()之一.对于您想做的事情，它可以很好地工作，但是Java纯粹主义者会为不可移植性感到震惊.

The easiest way is to use Runtime.exec() in one of its various flavours. For what you want to do, it will work fine, but Java purists will shudder at the non-portability.

Runtime.exec("java -jar trang.jar 5-something.xml 5.1-somethingElse.xsd");

干杯，
彼得
如果这回答了您的问题，请将其标记为已接受.仍要投票.

Cheers,
Peter
If this answers your question, mark it accepted. Vote anyway.

java [ options ] -jar file.jar [ argument ... ]通过查看 ^ ].

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