C#中二进制变量的并集和统一 [英] union and unity of binary variable in C#
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问题描述
大家好,
我为C#中的二进制变量的并集和统一编写了这段代码,但是当我运行它时,控制台只是打开和关闭.有什么问题吗?
Hi All,
I write this code for union and unity of binary variable in C# but when I run it, the console just open and close. what is its problem?
<pre lang="cs">using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
}
}
}
public class CBoolOperate
{
int[] a = null;
int[] b = null;
int[] c = null;
CBoolOperate()//default constructor
{
}
~CBoolOperate()//default destructor
{
}
public void get()
{
Console.WriteLine("please enter first 5 binary digit\n");
for (int i = 0; i < 5; i++)
{
a[i] = Console.Read();
}
Console.WriteLine("please enter first 5 binary digit\n");
for (int i = 0; i < 5; i++)
{
b[i] = Console.Read();
}
}
public void union()//A member function
{
for (int i = 0; i < 5; i++)
{
if (a[i] == 1 || b[i] == 1) c[i] = 1;
else c[i] = 0;
Console.WriteLine(c[i]);
}
Console.WriteLine("");
}
public void and()//A member function
{
for (int i = 0; i < 5; i++)
{
if (a[i] == 1 && b[i] == 1) c[i] = 1;
else c[i] = 0;
Console.WriteLine(c[i]);
}
Console.WriteLine("");
}
public int main()
{
CBoolOperate r=new CBoolOperate();
r.get();
r.union();
r.and();
return 0;
}
}
请帮我.
在此先感谢.
Please help me.
Thanks in Advance.
推荐答案
您好,亲爱的,
我认为您是编程的新手
我纠正了您的代码,并且效果很好
因为CBoolOperate的构造函数是私有的,所以我将CBoolOperate.main设置为static,相反它可能是
Hello dear,
I think you are a beginner in programing
I correct you code and it works well
Because constructor of CBoolOperate was private i make CBoolOperate.main as static , instead it could be
public CBoolOperate()//default constructor
{
}
and
static void Main(string[] args)
{
CBoolOperate A = new CBoolOperate();
A.main();
Console.ReadLine();
}
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
CBoolOperate.main();
Console.ReadLine();
}
}
}
public class CBoolOperate
{
int[] a = null;
int[] b = null;
int[] c = null;
CBoolOperate()//default constructor
{
}
~CBoolOperate()//default destructor
{
}
public void get()
{
this.a = new int[5];
this.b = new int[5];
this.c = new int[5];
Console.WriteLine("please enter first 5 binary digit\n");
for (int i = 0; i < 5; i++)
{
a[i] = Convert.ToInt32(Console.ReadLine());
}
Console.WriteLine("please enter first 5 binary digit\n");
for (int i = 0; i < 5; i++)
{
b[i] = Convert.ToInt32(Console.ReadLine());
}
}
public void union()//A member function
{
Console.WriteLine("result of union for numbers");
for (int i = 0; i < 5; i++)
{
if (a[i] == 1 || b[i] == 1) c[i] = 1;
else c[i] = 0;
Console.WriteLine(c[i]);
}
Console.WriteLine("");
}
public void and()//A member function
{
Console.WriteLine("result of and for numbers");
for (int i = 0; i < 5; i++)
{
if (a[i] == 1 && b[i] == 1) c[i] = 1;
else c[i] = 0;
Console.WriteLine(c[i]);
}
Console.WriteLine("");
}
public static int main()
{
CBoolOperate r=new CBoolOperate();
r.get();
r.union();
r.and();
return 0;
}
}
这是因为静态方法Program.Main
(它是程序的真实入口点)不执行任何操作.您可能以为其他方法main
是入口点.不.它不是程序的入口;它不是程序的入口.它不会被调用.
默认入口点是具有兼容签名的静态方法Main
.您可以在项目的属性中对其进行更改.
顺便说一句:永远不要编写不做任何事情的构造函数或析构函数.由于垃圾收集器(GC)的操作,几乎从未使用过析构函数.
—SA
This is because your static methodProgram.Main
(which is a real entry point of your program) does nothing. Your probably thought that your other methodmain
is an entry point. No. It is not an entry point of the program; it won''t be called.
The default entry point is a static methodMain
with compatible signature. You can change it in your project''s Properties.
By the way: Don''t ever write a constructor or destructor which don''t do anything. Destructors are almost never used because of Garbage Collector (GC) operation.
—SA
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