请检查出PostBackUrl中的错误? [英] Please check out error in PostBackUrl ?
本文介绍了请检查出PostBackUrl中的错误?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
该页面不是回发页面.请检查错误...
Transferring_Information1.aspx
The page is not PostBack.Please check out the error...
Transferring_Information1.aspx
<div>
<asp:Button runat="server" ID="cmdPost" PostBackUrl="~/Topics/Transferring Information/Transferring_Information2.aspx"
Text="Cross-Page Postback" /><br />
</div>
Transferring_Information2.aspx
Transferring_Information2.aspx
<%@ Page Language="C#" AutoEventWireup="true" CodeFile="Transferring_Information2.aspx.cs" Inherits="Topics_Transferring_Information_Transferring_Information2" %>
<%@ PreviousPageType VirtualPath="~/Topics/Transferring Information/Transferring_Information1.aspx" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title>Untitled Page</title>
</head>
<body>
<form id="form1" runat="server">
<div>
<asp:Label ID="lblInfo" runat="server" Text="Label"></asp:Label>
</div>
</form>
</body>
</html>
Transferring_Information2.aspx.cs
Transferring_Information2.aspx.cs
protected void Page_Load(object sender, EventArgs e)
{
if (PreviousPage != null)
{
lblInfo.Text = "You came from a page titled " +PreviousPage.Title + "<br />";
}
}
推荐答案
Transferring_Information1.aspx页中是否有任何验证
然后将CauseValidation
If there is any validation inTransferring_Information1.aspxpage
then put CauseValidation
<asp:Button runat="server" ID="cmdPost" CauseValidation="false" PostBackUrl="~/Topics/Transferring Information/Transferring_Information2.aspx"
Text="Cross-Page Postback" />
另一个原因可能是重定向URL，删除多余的空间并相应地重命名目录，然后重试，即，将传输信息重命名为TransferringInformation并在下面使用此代码，
Another reason might be Redirection URL, remove the extra space and rename the directory accordingly and try again, i.e. rename Transferring Information to TransferringInformation and use this code below,
<asp:Button runat="server" ID="cmdPost" CauseValidation="false"
PostBackUrl="~/Topics/TransferringInformation/Transferring_Information2.aspx"
Text="Cross-Page Postback" />
希望这会有所帮助.
Hope this will help.
<asp:button id="Button2"
text="Post value to another page"
postbackurl="Button.PostBackUrlPage2vb.aspx"
runat="Server">
</asp:button>
这篇关于请检查出PostBackUrl中的错误?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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