显示清单公开选出什么 [英] display list & make what choosed as a public

问题描述

> hi
我的项目在php中遇到问题
我想显示数据库中的列表
例如.
           老师    b              student
       玛丽亚-12121萨米-0909
       乔恩-13131 anosh-0707
       卡门-14141 zarina-0606

然后我想当用户单击"jon-13131"
打开新文件"teacher.php"，并将"jon-13131"设置为公共
(因为我想查看她的个人资料，信息等)
如果用户在"zarina-0606"上使用了小鸡
打开文件"student.php"，将"zarina-0606"设置为公共
(因为我也想查看她的个人资料，信息等)

我该怎么办?！?！

我使用此代码显示列表

>hi
I have problem in my project in php
I want to display list from database
eg.
             teacher                      student
         marya - 12121             sami - 0909
         jon - 13131                 anosh - 0707
         carmen - 14141          zarina - 0606

then I want when user click on "jon - 13131"
open new file "teacher.php" and make "jon - 13131" as public
(because I want to see her profile, information ..etc)
if the user chick on "zarina - 0606"
open file"student.php" make "zarina - 0606" as public
(because also I want to see her profile, information ..etc)

how can I do that ?!?!

I use this code to display list

<pre lang="php">$db_name="****";<br />
        $tbl_name="students";<br />
        mysql_connect("localhost", "root", "");<br />
        mysql_select_db("$db_name");<br />
        session_start();<br />
$ID=$_SESSION[''tID''];<br />
        $sql=mysql_query("SELECT * FROM $tbl_name WHERE user=$ID") or die(mysql_error());<br />
        while($mysqlf =mysql_fetch_array($sql))<br />
        {<br />
            $student=$mysqlf[''name''];<br />
            echo "$student &nbsp&nbsp&nbsp";<br />
            $id=$mysqlf[''ID''];<br />
            echo"$id<br>";</pre><br />

推荐答案

db_name ="****";< br/>

db_name="****";<br />

tbl_name ="students" ;< br/> mysql_connect("localhost"，"root"，");< br/> mysql_select_db("

tbl_name="students";<br /> mysql_connect("localhost", "root", "");<br /> mysql_select_db("

db_name");< br/> session_start();< br/>

db_name");<br /> session_start();<br />

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