显示未绑定数据的datagrid设计 [英] show design of datagrid without binding data to it

问题描述

我正在使用C#，asp.net，服务器2005和Visual Studio 2005

我的gridview设计看起来像这样:

FIRST_COLUMN | SECOND_COLUMN | THIRD_COLUMN | FOURTH_COLUMN | FIFTH_COLUMN |
------------ ------------- ------------ ------------- ------------
TEXTBOX1 |下拉列表| TEXTBOX2 | TEXTBOX3 | TEXTBOX4 |


当发生StudyIDTextBox_TextChanged(object sender，EventArgs e)事件时，我必须向用户显示此datagridview(设计)而不绑定数据..

请帮我..

问候
karan

I''m using C#,asp.net,server 2005 and visual studio 2005

my gridview design looks like this:

FIRST_COLUMN| SECOND_COLUMN| THIRD_COLUMN| FOURTH_COLUMN| FIFTH_COLUMN|
------------ ------------- ------------ ------------- ------------
TEXTBOX1 | DROPDOWNLIST | TEXTBOX2 | TEXTBOX3 | TEXTBOX4|


i have to display this datagridview (design) to the user without binding data to it when the StudyIDTextBox_TextChanged(object sender, EventArgs e) event occurs..

plz help me..

regards
karan

推荐答案

是的，您可以执行此操作.但我建议使用列模板.
如何在网格视图中动态创建模板列 [

yes you can do this. But I suggest to use Column Templates.
How to create template columns dynamically in a grid view[^]

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