字符串到十进制的转换 [英] string to decimal conversion

问题描述

当字符串包含算术表达式时如何将其转换为十进制?

如，

How to convert a string to decimal when the string contains an arithmetic expression?

Such as,

string str ="((1024+34)-(8*56)";

请提出




由于存在括号(，)，因此convert.todecimal无法使用
例如:-
字符串str =(((((@ accijns + @ ecotax)/100)* @unit)+ @ fostplus)
我将@accijns等替换为属性值

以下是我的代码

Please suggest




The convert.todecimal won''t work because of the presence of parenthesis(,)
Ex:-
string str = ((((@accijns+@ecotax)/100) * @unit) +@fostplus)
I am replacing @accijns, etc by property value

below is my code

string strFormula = oPriceType.formula;
//(formula is like ((((@accijns+@ecotax)/100) * @unit) +@fostplus)
string strCalculation = strFormula.Replace("@accijns", accijnValue.ToString()).Replace("@fostplus", fostplusValue.ToString()).Replace("@cost_price", @cost_price.ToString())
.Replace("@cost_extra", @cost_extra.ToString()).Replace("@cost_fob", @cost_fob.ToString()).Replace("@cost_ship", @cost_ship.ToString()).Replace("@cost_warehouse", @cost_warehouse.ToString())
.Replace("@ecotax", ecotaxValue.ToString()).Replace("@unit", @unit.ToString()).Replace("@discount_extra", @discount_extra.ToString()).Replace("@discount_payterm", @discount_payterm.ToString())
.Replace("@discount_financial", @discount_financial.ToString()).Replace("@weight", @weight.ToString()).Replace("@import_duty", @import_duty.ToString()).Replace("@degree", @degree.ToString())
.Replace("@recom_price", @recom_price.ToString());

你现在有了主意吗?
请提出
谢谢
sandeep

have you got the idea now??
please suggest
thank you
sandeep

推荐答案

这不是直截了当的，但是CP是 ]

It isn''t straight forward, but CP is here to help[]

看看Nagy Vilmos提供的链接-这是一篇很好的文章:thumbsup :.

如果您有兴趣从头开始创建自己的解决方案，可以通过以下方法入门:
反波兰符号 [

Take a look at the link Nagy Vilmos provided - it''s a fine article :thumbsup:.

And in case you''re interested in creating your own solution from scratch, here''s something to get you started:
Reverse Polish notation[^]

这篇关于字符串到十进制的转换的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！