强制从另一个孩子更新一个无模式子对话框 [英] Forcing an update of one modeless child dialog from another child

问题描述

我的第一个项目运行良好，直到尝试使其更具视觉吸引力为止.

初始化后，我的主对话框将创建一个输出对话框，其中包含三部分只读字段.主对话框有3个按钮，每个按钮都产生一个与输出对话框的一部分相对应的对话框.正是从这些用户输入对话框中，允许用户更新数据/公共数据.退出后，我在maindlg的OnPaint部分的输出对话框上执行Invalidate(TRUE)以强制更新其字段.至此一切都很好.

现在，我在3个用户输入对话框中设置x/y坐标，使其弹出在相应输出部分的下面，而不是在maindlg的顶部.现在，我看到，退出时maindlg无需绘画".

因此，如何在每个用户输入对话框中强制所有outdlg进行更新，而所有这些对话框都是maindlg的子级. >从对话框1到对话框2的用户定义消息. Dialog-2处理此用户定义的消息并使其自身无效.

My first project was working fine until I tried making it more visually appealing.

On initilization, my main dialog creates an output dialog with three sections of read-only fields. The main dialog has 3 buttons, each producing a dialog corresponding to a section of the output dialog. It is from these user entry dialogs where the user is allowed to update data/common. Upon exiting I''m doing an Invalidate( TRUE ) on the output dialog in the OnPaint section of maindlg to force an update of its fields. Everything is fine to this point.

Now I set the x/y coordinates on the 3 user entry dialogs to pop up just beneath the corresponding output section, rather than on top of maindlg. Now, I see, the maindlg has no need to "paint" when I exit.

So, how can I force an update of my outdlg from each of my user entry dialogs, all being childs of maindlg.

解决方案

The typical approach used is to PostMessage a user-defined message from dialog-1 to dialog-2. Dialog-2 handles this user-defined messages and invalidates itself.

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