输出从降序到升序变化 [英] Output change from descending to ascending order

问题描述

#include <stdio.h>
#include <conio.h>
#define arr_size 5
void main(void)
{
    float numbers[arr_size] ;
    int counter;
    printf("Input five numbers: \n");
    for (counter = 0; counter < arr_size; ++counter)
        {
            printf("%i?",counter + 1);
            scanf("%f", &numbers[counter]);
        }
    printf("Here they are:");
    for (counter = 4; counter >= 0; --counter)
    printf(" %g",numbers[counter]);
}

我想将输出从降序更改为升序.例如，输出将显示54321，但是我希望输出从12345开始显示，我可能知道它会将计数器更改为0吗?

I want to change the output from descending to ascending order. For example, the output will showing 54321, but I want the output showing start from 12345, may I know is it change the counter to 0?

推荐答案

首先，不要请勿使用幻数.您在第一个循环中使用了"arr_size"，在第二个循环中也使用了它.否则，您将冒着在一个位置更改大小的风险，并且由于未在另一位置更改t而导致代码失败.

Firstly, don''t use Magic Numbers. You used "arr_size" in your first loop, use it in your second as well. Otherwise you run the risk of changing the size in one place, and your code fails because you didn''t change t in the other.

for (counter = arr_size - 1; counter >= 0; --counter)
   printf(" %g",numbers[counter]);

要反转打印顺序，您可以通过两种方式执行此操作:

To reverse the order of printing, you could do this two ways:

for (counter = arr_size; counter > 0; --counter)
   printf(" %g",numbers[arr_size - counter]);

或

for (counter = 0; counter < arr_size; ++counter)
   printf(" %g",numbers[counter]);

BTW:按照惯例，在for 循环中使用后缀表示法-不是强制性的，而是正常的:
代替

BTW: It is a convention to use postfix notation in for loops - not mandatory, but normal:
Instead of

for (counter = arr_size - 1; counter >= 0; --counter)
   printf(" %g",numbers[counter]);

使用

for (counter = arr_size - 1; counter >= 0; counter--)
   printf(" %g",numbers[counter]);

[edit] Typo:添加新条件时忘记从for循环中删除旧条件-太早了！ -OriginalGriff [/edit]

[edit]Typo: Forgot to remove old condition from for loop when adding new condition - it''s early! - OriginalGriff[/edit]

这篇关于输出从降序到升序变化的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！