我如何从OpenPOP库的MessageRaw中提取附件文件 [英] How i can extract attachment file from MessageRaw in OpenPOP library

问题描述

嗨 我将OpenPOP库用于发送和接收电子邮件.
我程序的一部分是将收到的电子邮件保存到数据库中.
在程序的另一部分中，我必须向用户显示保存在数据库中的附件文件.
在我的保存方法中，我将RawMessage(包括标头，发件人，附件等)保存到数据库中.

Hi I use OpenPOP library for Send and Recive Email.
A part of my program is save recived email to database.
In another part of my program i must show attachment files that saved into database to user.
In my save method, i save RawMessage (include headers, sender, attachments and etc) into database.

<br />
<pre lang="cs"><br />
var MailContent = GetMessage(MessageNumber);<br />
DB.RawMessage = (from a in MailContent.RawMessage<br />
                 select (byte)a).ToArray();</pre><br />
.<br />
.<br />
.<br />
//finaly save DB into Database<br />

现在我的问题是:如何从保存的RawMessage中提取附件文件?

Now my question is: How i can extract attachment files from saved RawMessage?

推荐答案

请检查此

Hi, check this blog[^] for the code on attachment.

Something like

OpenPOP.MIMEParser.Message msg = MailContent.GetMessage(x, false);
if (msg != null) {
   for (int y = 0; y < msg.AttachmentCount; y++) {
      Attachment attachment = (Attachment)msg.Attachments[y];
      
      if (string.Compare(attachment.ContentType, "text/xml") == 0) {
         System.Xml.XmlDocument doc = new System.Xml.XmlDocument();
         string xml = attachment.DecodeAsText();
         doc.LoadXml(xml);
         doc.Save(@"C:\POP3Temp\test.xml");
      }
   }
}

嗨 谢谢您的回复.
我用下面的代码解决了我的问题:

首先从OpenPOP.Mime.Message创建一个消息对象:

Hi Thank you for your response.
I solve my problem with below code:

First creat a message object from OpenPOP.Mime.Message:

string StringRawContent = System.Text.ASCIIEncoding.ASCII.GetString(DB.RawMessage.ToArray());
OpenPOP.MIME.Message raw = new OpenPOP.MIME.Message(true, StringRawContent, false);

现在，我们在原始对象中包含了电子邮件的所有部分，例如主题，正文，发件人，附件等.
例如，我通过以下代码获取第一个附件文件:

Now we have all parts of email such as Subject, Body, Sender, Attachments and etc in raw object.
For example i get first attachment file via below code:

if (raw.Attachments.Count > 0)
    AttachmentFileContent = (from a in raw.Attachments.First().RawContent
                             select (byte)a).ToArray();

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