无法初始化构造函数 [英] can not initialize constructor
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问题描述
主要是我试图初始化构造函数,但我不能
recDB.insert(new Record(22, "Mike", 2500));
//------这是我的错误
in main i tried to initialze constructor but i could not
recDB.insert(new Record(22, "Mike", 2500));
//------this is my error
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ClassLibrary1
{
public class Class1
{
public class Record
{
public int ssn; // Primary Key
public String name;
public double pay;
Record(int newSSN, String newName, double newPay)
{
ssn = newSSN;
name = newName;
pay = newPay;
}
}
//------------------------------
public class RecordDB
{
private static int maxRecords = 200;
private int numRecords = 0;
private Record[] recordList = new Record[maxRecords];
//-------------------------------------------
public void insert(Record rec)
{
if (numRecords == maxRecords - 1)
{
return;
}
printAll();
}
//-------------------------------------------
public void delete(int newSSN)
{
printAll();
}
//-------------------------------------------
//public Record search(int newSSN)
public void search(int newSSN)
{
int first = 0, last = numRecords - 1;
// Print All records
printAll();
//Record recx = new Record(30, "JohnX", 5000);
//return recx;
} // end of search function
//------------------------------------------
private void printAll() {
Console.Write("---------------------------------");
for (int i = 0; i < numRecords; i++)
{
Console.Write("" + i + " " + recordList[i].ssn +
" " + recordList[i].name + " " + recordList[i].pay);
}
}
//------------------------------------------
public static void main(String[] args)
{
RecordDB recDB = new RecordDB();
recDB.insert(new Record(22, "Mike", 2500));//<-----------------Error
}
}
}
}
推荐答案
将构造函数更改为此:
Change your constructor to this:
public Record(int newSSN, String newName, double newPay)
您可能还需要考虑将这些嵌套的类移出.
干杯.
You also might want to consider moving those nested classes out.
Cheers.
Khalid SabtanFlaviu 2写道:
Khalid SabtanFlaviu 2 wrote:
Record(int newSSN,String newName,double newPay)
{
ssn = newSSN;
名称= newName;
pay = newPay;
}
Record(int newSSN, String newName, double newPay)
{
ssn = newSSN;
name = newName;
pay = newPay;
}
我会尝试:
I would try with:
public Record(int newSSN, String newName, double newPay)
{
ssn = newSSN;
name = newName;
pay = newPay;
}
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