C中的printf(带有5个百分号的符号给出错误) [英] printf in c (with five % sign gives error)

问题描述

#include<stdio.h>

int main()
{
pritnf("%%%%%");
}

我已经编写了这段代码，结果是

i have written this code and the out put is

/tmp/ccBawjSg.o: In function `main':
percent.c:(.text+0x11): undefined reference to `pritnf'
collect2: ld returned 1 exit status

为什么会这样?
这意味着什么???
如果有人知道，请回答


抱歉，我错误地执行了错误的代码

实际上是

why this is so???
and what does this means????
please if anybody knows this then answer


sorry guys by mistake i have executed the wrong code

actualy it is

#include<stdio.h>
int main()
{
printf("%%%%%");
}

而警告是
崩溃

percent.c:在"main"函数中:
percent.c:5:警告:格式末尾的乱码％"

并且输出仅是"%%"，为什么不是"%%%%%"

[/Edit]

and the warning is
Collapse

percent.c: In function ‘main’:
percent.c:5: warning: spurious trailing ‘%’ in format

and output is only "%%" why not it is "%%%%%"

[/Edit]

推荐答案

这是因为您的代码中有错字.您编写的是"pritnf"而不是"printf".

It''s because there is a typo in your code. You wrote "pritnf" rather than "printf".

％"字符表示格式规范的开始.为了打印单个％"字符，您需要在格式字符串中指定"%%".

请参见此处 [

The ''%'' character indicates the start of a format specification. In order to print a single ''%'' character, you need to specify "%%" in the format string.

See here[^] for more details.

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