请为我找到错误... [英] please find the error for me...

问题描述

 公共 字符串 getage(如果(年龄>   60 )// 错误:并非所有代码路径都返回值.
                返回 " ；
            其他
                如果(年龄>  =  40 & ;& age <  =  59 )
                    返回 " ;
                其他
                    如果(年龄>  =  20 & ;& age <  =  39 )
                        返回 " ；
                    其他
                        如果(年龄>  =  12 & ;& age <  =  19 )
                            返回 " ；
        } 

它没有收到错误..请帮助一个新蜜蜂..thx

解决方案

如果年龄小于12岁，您的If-case不处理该方案.仔细看.因此，对于age < 12，您的代码不会返回任何内容，因此也不会返回错误.

我想，您正在尝试了解错误消息的原因.
当您的方法返回String时，编译器期望每个条件都应返回String.

在示例中查看以下代码:

 如果(年龄>  = <  = 返回 " ;  



它没有"else"块，因此，在这种情况下，编译器看不到任何String 值被返回.因此，它无法编译该类并显示错误.



希望我能为您提供帮助.

Shikhar，

您已经收到足够的答案；他们告诉您您需要其他"，这都是正确的.

但是，我个人认为这只是技术细节.

您的问题是概念性的:您不理会孩子(完全，包括新生儿，婴儿...)，但您不应该这样.与大多数软件开发人员不同，孩子们的头脑仍然乌云密布.

因此，这是为您提供的最终答案:如果您不小心忘记了其他"，则添加它，如果您忽略孩子，请重新考虑生活.

最好的祝愿！ ;)

public String getage(int age)
        {
            if (age > 60)               //  Error : Not all code paths return a value.
                return "senior";
            else
                if (age >= 40 && age <= 59)
                    return "middle aged";
                else
                    if (age >= 20 && age <= 39)
                        return "adult";
                    else
                        if (age >= 12 && age <= 19)
                            return "teenaged";
        }

it do not get the error in it..please help a newbee..thx

解决方案

Your If-case does not handle the scenario if age is less than 12. Look closely. Thus, for age < 12, your code does not return anything and hence the error.

I guess, you are trying to know the reason of the error message.

As your method returns a String, the complier expects that each and every condition should return a String.

Look the following piece of code in your example:

if (age >= 12 && age <= 19)
     return "teenaged";

It doesn''t have an "else" block, so, the compiler doesn''t see any String value getting returned in this situation. So, it is not able to compile the class and showing the error.

I hope I was able to help you.

Shikhar,

You already received enough answers; they tell you that you need "else" and this is all correct.

However, I personally think this is just a technical detail.

You problem is rather conceptual: you ignore children (totally, with newborn, infants...), but you should not. Unlike most of the software developers, children still have unclouded mind.

So, here is an ultimate answer for you: if you just accidentally forgot about "else" -- add it, if you ignore children -- rethink your life.

Best wishes! ;)

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