启用多选的OpenFileDialogue [英] OpenFileDialogue with Multiselction enabaled

问题描述

大家好，

我在这里有一个问题.

情况是:
我使用OpenFileDialogue选择一些文件(例如TextOne.txt，TextTwo.txt，TextThree.txt).
现在，我要访问将TextTwo.txt发送到要读取的流对象.
该怎么做?
因为;

HI guys,

I have a question here.

The situation is:
I use OpenFileDialogue to select some files (e.g TextOne.txt,TextTwo.txt, TextThree.txt).
Now I want to access send the TextTwo.txt to a stream object to be read.
How to do that?
Because;

stream = OpenFileDialog.OpenFile();

正在获取TextOne.txt.

is getting the TextOne.txt.

FileNames[i]

或

FileName[i]

仅返回字符串，但不返回流.


需要帮助吗?

just returns the string but not the stream.


Need help on this?

推荐答案

OpenFileDialog始终仅返回文件名:它无法返回流，因为它不知道您将要做什么.它:以文本或二进制形式打开.
如果您将其与
一起使用

OpenFileDialog always returns only the file name: It can''t return the stream because it does not know what you are going to do with it: Open it as text or binary.
If you are using it with

this.openFileDialog1.Multiselect = true;

然后，您需要遍历所有名称并自己打开它们:

Then you need to loop through all names and open them yourself:

foreach (String file in openFileDialog1.FileNames)
   {
   FileStream fileStream = new FileStream(file, FileMode.Open);

   ... // Do something with the stream.

   }

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