正则表达式以查找字符串和更多内容 [英] Regex to find a string of characters + more

问题描述

大家好

我正在寻找能找到一个字符串的正则表达式...

Hey all

I''m looking for a regular expression that will find a string of characters...

"/* Call SUT */"

然后假设在字符串之前插入3个换行符.

在第一个换行符上插入一个字符串...

It is then suppose to insert 3 newlines before the string of characters.

On the First newline insert a string...

"/* Lower LOG level to improve performance and decrease output file size. */"

在第二个换行符上插入一个字符串...

On the Second newline insert a string...

"Old_Log_Level = SET_LOG_LEVEL(cppth_ll_concise);"

并将第三条换行符留空.

最终结果应如下所示:

And leave the Third newline empty.

Final result should look like:

/* Lower LOG level to improve performance and decrease output file size. */
Old_Log_Level = SET_LOG_LEVEL(cppth_ll_concise);

/* Call SUT */

我们将不胜感激.

Help would be appreciated.

推荐答案

您无需使用正则表达式即可:只需使用string.Replace方法即可:

You don''t need a Regex to do that: you can just use the string.Replace method:

string inp = "hello there\n/* Call SUT */goodbye";
inp = inp.Replace("/* Call SUT */",
                  "/* Lower LOG level to improve performance and decrease output file size. */\n" +
                  "Old_Log_Level = SET_LOG_LEVEL(cppth_ll_concise);\n" +
                  "\n" +
                  "/* Call SUT */");

设法自己解决问题.

Managed to solve the problem myself thx.

Regex("^.*\/\* Call SUT \*\/.*

"); Regex(" \/\* Lower LOG level to improve performance and decrease output file size\. \*\/\n Old_Log_Level = SET_LOG_LEVEL(cppth_ll_concise);\n\n /* Call SUT */");

"); Regex(" \/\* Lower LOG level to improve performance and decrease output file size\. \*\/\n Old_Log_Level = SET_LOG_LEVEL(cppth_ll_concise);\n\n /* Call SUT */");

或我实际上想将其用于以下用途:
查找内容:

Or what I actually wanted to use it for:
Find what:

^.*\/\* Call SUT \*\/.*

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