CRecordView& CDialog :: DoModal() [英] CRecordView & CDialog::DoModal()

问题描述

我创建了一个具有ODBC支持的应用程序，并创建了一个与Crecordset类和Form View关联的CRecordView类.问题是我只想展示CRecordView派生的类，例如CDialog :: DoModal()函数.
请帮助我，使这一切成为可能:((，&我将很感谢有说服力的答案.

I have created an application with ODBC support & created a CRecordView class associated with a Crecordset class & Form View. The problem is that I am stuck to just Show that CRecordView derived class like CDialog::DoModal() function do.
Help me please to make this possible :((, & I will be grateful for a convincing answer.

推荐答案

我正在要求一种方法来显示CRecordView派生类，例如展示了一个具有DoModal()函数的CDialog派生类.

I am asking for method to show a CRecordView derived class like showing a CDialog derived class with DoModal() function.

我不确定您的问题到底在问什么，但您可能会找到答案

I''m not sure what your question is really asking, but you may find the answer here[^].

嗯，
问题是:如何实施
CWnd* CFrameWnd::CreateView(CCreateContext* pContext, UINT nID = AFX_IDW_PANE_FIRST);函数，&然后将其显示为模态?

NB:我的视图类是CRecordView派生类.

对不起，我的英语不好:(

Well,
The question is: How to implement
CWnd* CFrameWnd::CreateView(CCreateContext* pContext, UINT nID = AFX_IDW_PANE_FIRST); function, & then show it as modal ?

NB: My view class is CRecordView derived class.

Sorry for my bad english :(

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