休息后恢复foreach [英] resume foreach after break

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本文介绍了休息后恢复foreach的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我的代码如下:

My code is as follow:

private void IzvadaJautajumuAtbildes()
        {
            var something =
                from x in channel2.GetJautajumuSaraksts(SelectedTestID)
                select new
                {
                    id = x.QuestionID, ; //1,2,4,5,7
                    name = x.Name
                };
            foreach (var i in something)
            {
                lblQuestion.Text = i.nosauk;
                currentQuestionID = i.id
                answer = channel2.GetAnswer(currenQuestionID);
                foreach (var i2 in answer)
                {
                    btnAtbilde1.Text = i2.Answer1;
                    btnAtbilde2.Text = i2.Answer2;
                    btnAtbilde3.Text = i2.Answer3;
                    btnAtbilde4.Text = i2.Answer4;
                }
                break;
            }
         }



在此代码中,在button2_Click事件上,当我单击一次button2时,一切正常,我收到了问题&答案.
如何再次迭代IzvadaJautajumuAtbildes(),但使用下一个ID.
2不是1.



In this code, on button2_Click event, when I click on button2 once, everything is ok, I get question & answers.
How can I iterate IzvadaJautajumuAtbildes() again, but with the next id.
2 not 1.

推荐答案

您不能更改foreach语句中使用的迭代器,因为它是只读的.

您可以做的是创建一个指示已使用"的属性,使用Linq构建不已使用"的项目的集合,然后在该新集合上使用foreach.
You can''t change the iterator used in a foreach statement because it''s read-only.

What you could do is create a property that indicates "used", use Linq to build a collection of items that aren''t "used", and then use foreach on that new collection.


通过for循环将整个对象包围起来

Surround the whole thing by with a for loop

private void IzvadaJautajumuAtbildes(int[] testValues)
{
  for (int i = 0; i < testValues.Length(0); i++)
  {
    var something =
     from x in channel2.GetJautajumuSaraksts(testValues[i])
     ..................
     // rest of your code here
     ..................
       break;
     }
  }
}



检查语法,这是我的头上事情.



Check syntax, I''m doing this off the top of my head.


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