如何从默认标量中提取字符串. [英] How to extract string in from a default scalar.

问题描述

你好，
我在perl中有这个小代码，现在我非常确定该怎么做.我已经从csv文件int0 $ _中读取了一行，现在我需要从中提取字符串的一部分.

CSV文件中的前行将是
一；二；三；四；五；六

我需要有一个变量(标量)才能具有值
fourfive

(在四到五个之间没有分号)
我尝试了模式匹配，但没有得到正确的结果
可以提供任何帮助.

Hello,
I have this small code to do in perl and i am now very sure of how to do it. I have read a line from the csv file int0 $_and now i need to extract a part of the string from it.

Ex line in csv file would be
one;two;three;four;five;six

and i need to have a variable (a scalar) to have the value
fourfive

(without the semicolon between four and five)
i tried with pattern matching but didnt get the proper results
can any one help.

推荐答案

_，现在我需要从中提取字符串的一部分.

CSV文件中的前行将是
一；二；三；四；五；六

我需要有一个变量(标量)才能具有值
fourfive

(在四到五个之间没有分号)
我尝试了模式匹配，但没有得到正确的结果
谁能帮忙.

_and now i need to extract a part of the string from it.

Ex line in csv file would be
one;two;three;four;five;six

and i need to have a variable (a scalar) to have the value
fourfive

(without the semicolon between four and five)
i tried with pattern matching but didnt get the proper results
can any one help.

您需要的是:

What you need is this:

info =一个；两个；三个；四个；五个；六个；" @items = split(/;/，

info = "one;two;three;four;five;six;" @items = split(/;/,

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