计数列表框重复项 [英] Counting List Box Duplicate Items

问题描述

大家好.

我有两个列表框.其中之一充满了文件名及其目录.

我想在第一个列表框中计算所有重复的文件名，然后在第二个列表框中放入文件名和重复数.

点赞:0.TXT(6)

该程序: http://img178.imageshack.us/img178/2160/82415716.png [ ^ ]

我使用VC ++，所以请给我C ++代码，因为我还是个初学者. :((

提前致谢. :-O

Hello all.

I have two list boxes. One of them is filled with file names and their directories.

I want to count all duplicate file names in the first list box and put the file name and the number of duplication in the second list box.

like: 0.TXT (6)

the program:http://img178.imageshack.us/img178/2160/82415716.png[^]

I use VC++, so please give me C++ code for I''m still a beginner. :((

Thanks in advance. :-O

推荐答案

即使在vb.net中也检查该链接，但是您可以理解它的算法:
链接 [

check that link even it is in vb.net but you can understand the algorithem of it :
link[^]

the trick is to create 2 nested loops :
while(i<listbox.count){>
for(k<listbos.count){>
// then check if(listbox[i]==listbox[k]){
then add this item to the new list ...
}}
regards...

非常感谢您的回答，但我真的无法理解其中的许多表达方式.

我用谷歌搜索，但发现的只是VB代码.

关于您上面提供的想法，我尝试了一下，但它给了我一个超出范围的异常.

这是我到目前为止所做的:

thanks a lot for the answer but I really couldn''t understand many of it''s expressions.

I googled it but all I found was VB code.

and about the idea you provided above, I tried it but it gives me an out of range exception.

here is what I did so far:

int L = listBox1->Items->Count::get();
int i = 0;
while(i<l)>
{
  i++;
  for(int k=0; k<l;>  
  {
    if(listBox1->Items[i]==listBox1->Items[k])
    {  
      listBox2->Items->Add(listBox1->Items[i]);
    }
  }
}

抱歉，如果我错了！

Sorry if I were wrong!

是的，它肯定会超出范围，我只是给出了一个想法而没有给出完整的逻辑...
诀窍是从我们到达最后一次的第二个循环开始...

这是逻辑:

对于(i = 0; i< count; i ++){>

for(j = i + 1; j< count-i; j ++){>

然后做任何你想做的事}
}


问候...

yes sure it will give out of range I just gave an idea without giving the fulllogic ...
the trick is to start in the second loop where we have reached the last time ...

here is the logic :

for ( i=0;i<count;i++){>

for( j=i+1;j<count-i;j++){>

then do what ever you want }
}


regards...

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