显示连接形式 [英] show form on connection

问题描述

好的，这是我的连接代码

Okay this is my connection code

class myConnection
{
    public static string datasource = "";
    public static string initialcatalog = "";
    public static string uid = "";
    public static string pwd = "";
    public static MySqlConnection GetConnection()
    {
        string str = "SERVER='" + datasource + "';DATABASE='" + initialcatalog + "';UID='" + uid + "';PASSWORD='" + pwd + "'";
        MySqlConnection con = new MySqlConnection(str);
        con.Open();
        return con;
    }
}

我似乎无法弄清楚如何使其显示Form2(如果它实际上已连接到数据库)，我已经完成了此操作，但是我在脑海中完全空白，无法在Google上找到任何内容(我很讨厌搜索大声笑)

i cant seem to figure out how to make it Show form2 if it actually connects to the database, i have done this befor but im completely drawing a blank in my mind and i cant find anything on google (i suck at searching lol)

Any help would be apreciated

推荐答案

假设Form2是您希望显示的表单，并且您位于Form1中，则可以执行以下操作:

Assuming Form2 is the form you wish to show and you are in Form1, you could do this:

public partial class Form1 : Form
{
...
public void ShowForm2()
{
    MySqlConnection connection = myConnection.GetConnection();

    if (connection != null)
    {
         Form2 frm2 = new Form2();
         frm2.Show();
         // or 
         // frm2.ShowDialog();
    }
}
...
}

注意-我假设您尚未发布所有的"myConnection"类，因此未进行验证.但这是您向用户显示另一种表单的方式

Note - I am assuming you haven''t posted all of your "myConnection" class and so didn''t verify that. But this is how you show another form to the user

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