lang.NumberFormatException在android系统 [英] lang.NumberFormatException in android
问题描述
我有以下的code这不只是在后台线程读取从DB一些值,并使用这些值我使用的是jar.For我使用的价值为每个阵列线图绘制折线图和问题是,第三个,我传递给绘制线型图的构造是浮动....
I have the following code which does nothing but reading some values from a DB in a background thread and using the values I draw a Line chart using a jar.For the line chart I use for value for each array and the problem is that the third that I pass to the constructor that draws the LineChart is float....
float[] viteza;
String[] time;
int contor=0;
public void onResume() {
super.onResume();
init_task = new InitTask();
init_task.execute(db);
}
public class InitTask extends AsyncTask<DBAdapter,String, Void> {
String TABLE_3;
protected Void doInBackground(DBAdapter... db) {
try {
db[0].createDatabase();
db[0].openDataBase();
Cursor c = db[0].getCursor3(db[0].TABLE_3, user_id);
String[] array=new String[2];
viteza = new float[c.getCount()];
time = new String[c.getCount()];
if (c.moveToFirst()) {
do {
publishProgress(c.getString(3),c.getString(4));
Thread.sleep(500);
} while (c.moveToNext());
}
c.close();
db[0].close();
} catch (Exception e) {
Log.d("Eroare", "doInBackground", e);
}
return null;
}
protected void onProgressUpdate(String...values) {
Aitem items[] = new Aitem[1];
viteza[contor]=Float.valueOf(values[0]);
time[contor]=values[1];
if(contor>3)
{
items[0]=new Aitem(Color.RED, "Evolution",viteza);
lv.setTitle("Evolutia vitezei");
lv.setAxisValueX(time);
setContentView(lv);
}
contor++;
}
}
}
我在这行得到错误:
I get error at this line:
viteza[contor]=Float.valueOf(values[0]);
java.lang.NumberFormatException:
at org.apache.harmony.luni.util.FloatingPointParser.parseFltImpl(Native Method)
at org.apache.harmony.luni.util.FloatingPointParser.parseFloat(FloatingPointParser.java:321)
有没有人任何线索是什么gooing错???
Has anyone any clue what is gooing wrong???
编辑:
在我的愚见值[0] = c.getString(3)和值[1] = c.getString(4)左右....都是字符串......不是吗?
In my humble opinion values[0]=c.getString(3) and values[1]=c.getString(4) so ....are Strings...aren't they?
推荐答案
我不知道只要看一眼,但我可以告诉你,这就是Log.v是非常方便的。把Log.v(TAG,\\+值[] +\\),你会看到什么是越来越给这个函数。如果这是任何其他比纯数字,那会是什么导致发生异常。
I'm not sure just by looking at this, but I can tell you, this is where Log.v is extremely handy. Put a Log.v(TAG,"\""+values[]+"\""), and you'll see exactly what's getting to that function. If it's anything other than a pure number, that'd be what's causing the exception to occur.
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