如何创建于Android清单浏览的意图是什么？ [英] How do I create browsable intent in the android manifest?

问题描述

我有一个Android应用程序应该打开通过电子邮件发送链接。我只是想打开链接到一个特定的网站，虽然。我知道，打开YouTube链接可用于提供一个对话框，询问是否要在浏览器或在YouTube应用中打开它的用户，所以这就是我要的。在我的Andr​​oid清单文件，我有以下意图过滤器：

I have an Android app that should open links sent via email. I only want to open links to a certain website, though. I know that opening youTube links provides the user with a dialog asking whether to open it in the browser or in the youTube app, so this is what I am going for. In my android manifest file, I have the following intent filters:

    <activity android:name=".MyApp"
              android:label="@string/app_name">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
        <intent-filter>
            <action android:name="android.intent.action.VIEW" />
            <category android:name="android.intent.category.BROWSABLE"/>
            <data android:scheme="http"
                  android:host="mySite.com" />

        </intent-filter>
    </activity>

然后，要处理这个意图，我在的onCreate一行：

Then, to handle the intent, I have a line in onCreate:

if (getIntent().getCategories().contains("android.intent.category.BROWSABLE")){...}

问题是，如 HTTP链接：//mySite.com#12345 不开这种方式。我在做什么错了？

The problem is that links such as http://mySite.com#12345 are not opening this way. What am I doing wrong?

推荐答案

答案是默认类别添加到第二个意图过滤器，就像@advantej建议。

The answer was to add the default category to the second intent filter, just as @advantej suggested.

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