涉及指针的矩阵乘法 [英] Matrix multiplication involving pointers

问题描述

我该如何将矩阵C(常数)与A相乘并将结果存储在B中?有关当前案例，请参见代码片段.

how to do i multiply matrix C(constant) and A and store the results in B? See the snippet code for the case at hand.

tom.cpp file
void tom::multiply(void* btr)

{



         short* A =(short*)btr;



             int j,i;



short C[4][4]={1,1,1,1,2,1,-1,-2,1,-1,-1,1,1,-2,2,-1};

short B[4][4];

推荐答案

您知道:

B<small>ik</small> = C<small>ij</small> * A<small>jk</small>

在重复索引 j 上加上和.

那(可能)翻译为:

With sum on the repeated index j.

That''s (probably) translates to:

for (i=0; i<4; i++)
  for (k=0; k<4; k++)
    for (j=0; j<4; j++)
      B[i][k] = C[i][j] * A[j*4+k]

就您而言.

:)

in your case.

:)

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