如何禁用ContextMenuStrip的弹出窗口 [英] How to disable the pop up of ContextMenuStrip

问题描述

我编写了一个窗口应用程序，然后将ContextMenuStrip对象拖到要包含在面板对象中的程序中，以便当我在面板上单击鼠标右键时，ContextMenuStrip将自动弹出.

现在的问题是，当我单击并按住鼠标左键，然后右键单击鼠标时，我希望ContextMenuStrip仍然不会弹出，但是ContextMenuStrip仍然会弹出那里！

I wirte a window application, and I dwew a ContextMenuStrip object to my program to be included in a panel object, so that when I right click mouse on the panel, the ContextMenuStrip will pop up automatially.

And now, the question is that when I click and hold left button of mouse, and then right click mouse, I hope the ContextMenuStrip will not pop up anyway, but, the ContextMenuStrip still pop up there !

Can anybody help to show how to reach this point ?

推荐答案

处理Panel的MouseDown event.
在此处检查示例代码.

Handle MouseDown event of Panel.
Check the sample code here.

private void panel3_MouseDown(object sender, MouseEventArgs e)
{
    if (e.Button == MouseButtons.Right)
    {
        panel3.ContextMenuStrip = contextMenuStrip3;
    }
    else
    {
        panel3.ContextMenuStrip = null;
    }
}

[添加的代码格式]

[Added code formatting]

您可以在鼠标左键单击事件中禁用contextMenuStrip，在离开事件中启用它
:suss:

you may disable contextMenuStrip in left mouse click event and enable it in leave event
:suss:

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