在"e-s"中找不到"operator"的匹配项 [英] no match for 'operator'- in 'e-s'

问题描述

#include<stdio.h>
#include<conio.h>
#include<windows.h>
int main(){
  LARGE_INTEGER frequency;
  LARGE_INTEGER e,s,diff;
  QueryPerformanceCounter(&s);
  for(int i=0;i<100;i++)

  {}

  QueryPerformanceCounter(&e);

  diff=(e-s)/frequency*1000;

  unsigned int milliseconds = (unsigned int)(diff & 0xffffffff);

  printf("%u",milliseconds);

  getch();

  return 0;

}

我正在尝试执行此程序，但收到错误消息
在"e-s"中不匹配"operator"-

谁能帮我这个忙.在此先感谢...

i am trying to execute this program im getting an error as
no match for ''operator''- in ''e-s''

can anyone help me out with this. Thank in prior...

推荐答案

LARGE_INTEGER是一个联合，并且未定义-"运算符.使用QuadPart成员(如e.QuadPart-s.QuadPart中一样)或使用__int64.

LARGE_INTEGER is a union and doesn''t define the "-" operator. Use the QuadPart member (as in e.QuadPart-s.QuadPart) or use __int64 instead.

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