C函数 [英] Functions in C

问题描述

我写了一个计算数字幂的程序
示例2 ^ 5 = 32

程序

I wrote a program which calculte the power of a number
example 2^5 = 32

program

#include<stdio.h>
#include<conio.h>

void main(){
	int a,b,c;
	int power();
	printf("base value : ");
	scanf("%d",&a);
	printf("power value : ");
	scanf("%d",&b);

	c=power(a,b);
	printf("value of a power b =%d",c);
	getch();
	}

当我编译该程序时出现错误
第12行出错:调用power()的附加参数


但是在此程序中不会出现错误

程序

when i compile this program an error comes
Error at line 12 : Extra Parameter to call power()


But in this program no error comes

Program

int power(int x,int y){
	int k,l,m=1;
	k=x;l=y;
	for(int i=0;i<l;i++)
		m = m*k;
	return(m);
}
void main(){
	int a,b,c;
	
	printf("base value : ");
	scanf("%d",&a);
	printf("power value : ");
	scanf("%d",&b);

	c=power(a,b);
	printf("value of a power b =%d",c);
	getch();
	}

我认为第一个程序的函数声明存在问题.
但是根据书的功能可以在不指定参数的情况下进行声明.所以我声明为"int power();"

请说明错误是什么意思，问题出在哪里.

I think there is a problem in function declaration in 1st program.
but according to book function can be declared without specifying arguments. So i declared as "int power();"

Please tell what error means and where is the problem.

推荐答案

如果您查看两个程序之间的差异，为什么会注意到?我注意到了:

int power();

错误消息有点怪异，但我认为这完全令人困惑，因为您的语法没有意义.试试

整数功率；

或者只是摆脱那条线，我没有注意到它有任何作用.

power方法是否存在于第一个程序中，而您没有显示它?

IF you look at the differences between the two programs, why do you notice ? I notice this:

int power();

The error message is a bit weird, but I think it''s totally confused because your syntax makes no sense. Try

int power;

Or just get rid of that line, I''m not noticing that it does anything.

Does the power method exist in the first program and you just didn''t show it ?

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