分页不会在第二页上工作,所以 [英] pagination doenst work for second page and so

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本文介绍了分页不会在第二页上工作,所以的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

大家好,

我正在写一个分页,因为我是php新手,但我有一个问题.当在代码中为变量赋常量时,分页工作正常,因为我通过客户端将其传递给它,所以它只会加载第一页,而第二页和其他页将不会显示,
怎么了?

这是代码

Hi all,

I am writing a pagination as I am new to php I have a problem in that. When give a constant to a variable inside the code the pagination works properly wen I pass it via the client side it just loads the first page and the second and other pages will not appear,
What is wrong with that?

here is the code

$sqlcount=("SELECT * FROM job_results where Title LIKE '%$kw%'");
    $row_result = mysql_query($sqlcount) or die(mysql_error());
    $rowspage = mysql_num_rows($row_result);
    $numrows =$rowspage;
    // number of rows to show per page
     $rowsperpage = 10;
   // find out total pages
     $totalpages = ceil($numrows / $rowsperpage);
     // get the current page or set a default
    if (isset($_GET['currentpage']) && is_numeric($_GET['currentpage'])) {
   // cast var as int
   $currentpage = (int) $_GET['currentpage'];
} else {
   // default page num
   $currentpage = 1;
} // end if
// if current page is greater than total pages...
if ($currentpage > $totalpages) {
   // set current page to last page
   $currentpage = $totalpages;
} // end if
// if current page is less than first page...
if ($currentpage < 1) {
   // set current page to first page
   $currentpage = 1;
} // end if
// the offset of the list, based on current page
$offset = ($currentpage - 1) * $rowsperpage;
    $sqlcount=("SELECT * FROM job_results where Title LIKE '%$kw%' LIMIT $offset, $rowsperpage");
    $row_result = mysql_query($sqlcount) or die(mysql_error());
    //echo $sqlcount;
//end of pagination
    while($row = mysql_fetch_array($row_result, MYSQL_ASSOC)){
echo(...);
}

<pre lang="xml">$range = 3;
// if not on page 1, don't show back links
if ($currentpage > 1) {
   // show << link to go back to page 1

   echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=1'><<</a> ";
   // get previous page num
   $prevpage = $currentpage - 1;
   // show < link to go back to 1 page

   echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$prevpage'><</a> ";
} // end if
// loop to show links to range of pages around current page
for ($x = ($currentpage - $range); $x < (($currentpage + $range) + 1); $x++) {

   // if it's a valid page number...

   if (($x > 0) && ($x <= $totalpages)) {

      // if we're on current page...

      if ($x == $currentpage) {

         // 'highlight' it but don't make a link

         echo " [<b>$x</b>] ";
      // if not current page...
      } else {
         // make it a link
         echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$x'>$x</a> ";
      } // end else
   } // end if
} // end for
// if not on last page, show forward and last page links
if ($currentpage != $totalpages) {
   // get next page
   $nextpage = $currentpage + 1;
    // echo forward link for next page
   echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$nextpage'>></a> ";
   // echo forward link for lastpage
   echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$totalpages'>>></a> ";
} // end if
/****** end build pagination links ******/

推荐答案

sqlcount =( 选择* FROM job_results,其中标题为'%
sqlcount=("SELECT * FROM job_results where Title LIKE '%


kw%'");
kw%'");


row_result = mysql_query(
row_result = mysql_query(


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