notRegistered＆QUOT;是什么错误由code＆QUOT的意思;使用GCM发送推送消息时？ [英] what does mean by error code "notRegistered" when sending push messages using GCM?

问题描述

我想通过以下code以将通知发送到通过Java服务器注册的设备：

I am trying to send push notification to the registered device through Java server by following code:

import java.io.IOException;
import java.util.ArrayList;

import com.google.android.gcm.server.Constants;
import com.google.android.gcm.server.Message;
import com.google.android.gcm.server.MulticastResult;
import com.google.android.gcm.server.Result;
import com.google.android.gcm.server.Sender;


public class Test {




    private void sendNotification()
    {
           try{
                 Sender sender = new Sender("AIzaSyD9GblH8c9qCBqDhLPKMca3dH8JsY4cgjg");
                 ArrayList<String> devicesList = new ArrayList<String>();
                 devicesList.add("APA91bEtN2c3FYSFPpW-KuNtkWT6B9NJUviKN0L0DCjviJ2BtMyhZLqsFSFKfsySI1s88I0u68xETjvpqhvepffRSgwoTmpRXAv0Fbr0gH8CLhHO5CJC-M8");
                 String data = "hi.......";
                 Message message = new Message.Builder()
                                    .collapseKey("1")
                                    .timeToLive(3)
                                    .delayWhileIdle(true)
                                    .addData("message",
                                            data)
                                    .build();
                MulticastResult result = sender.send(message, devicesList, 1);
                            sender.send(message, devicesList, 1);

                            System.out.println(result.toString());
                            if (result.getResults() != null) {
                                int canonicalRegId = result.getCanonicalIds();
                                if (canonicalRegId != 0) {
                               System.out.println("hi...");
                                }
                            } else {
                                int error = result.getFailure();
                                System.out.println(error);
                            }

            }
           catch(Exception e)
           {
               System.out.println(e);
           }
    }
    public static void main(String ar[])
    {
        new Test().sendNotification();


    }

}

和我收到以下错误：

MulticastResult(multicast_id=7574342191790679138,total=1,success=0,failure=1,canonical_ids=0,results:
  [错误 - code = NotRegistered]

MulticastResult(multicast_id=7574342191790679138,total=1,success=0,failure=1,canonical_ids=0,results: [[ error-code=NotRegistered ]]

类似的问题早前公布，但我没有发现任何满意的答复那里。

Similar question was posted earlier but i didn't find any satisfactory answer there.

推荐答案

为您在 devicesList 不与GCM注册提供设备的注册ID。首先，您需要将设备与GCM注册，以获得有效RegistrationId.After得到这个REGID你将它传递到服务器的话，只有你的服务器可以通过GCM推送通知。

The Registration Id for the device which you are providing in the devicesList is not registered with the gcm.You first need to register your device with the gcm to obtain a valid RegistrationId.After getting this RegId You will pass it to server then,only your server can push the notification through GCM.

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