C#标准偏差 [英] C# standard deviation

问题描述

伙计们.我是c#菜鸟，但我确实需要专业的帮助.我将Visual Studio 2005用于一个项目，所以我没有math.linq，我需要计算通用对象列表的标准差.该列表仅包含浮点数列表，没有什么太复杂的.但是我以前从未做过此事，因此我需要有人告诉我之前已计算出通用列表的标准差.这是我尝试开始的代码:

Guys. Im a c# noob but I really need a professional''s help. I am using visual studio 2005 for a project so I dont have math.linq I need to calculate the standard deviation of a generic list of objects. The list contains just a list of float numbers, nothing too complicated. However I have never done this before so i need someone to show me that has calculated standard deviation of a generic list before. Here is my code that I tried to start on:

//this is my list of objects inside. The valve data just contains a bunch of floats.
public class ValveDataResults
{
    private List<valvedata> m_ValveResults;

    public void AddValveData(ValveData valve)
    {
        m_ValveResults.Add(valve);
    }
    
    //this is the function where the standard deviation needs to be calculated:
    public float LatchTimeStdev()
    {
        //below this is a working example of how to get an average or mean
        //of same list and same "LatchTime" that needs to be calculated here as well. 
    }

    //function to calculate average of latch time, can be copied for above st dev.
    public float LatchTimeMean()
    {
        float returnValue = 0;
        foreach (ValveData value in m_ValveResults)
        {
            returnValue += value.LatchTime; 
        }
        returnValue = (returnValue / m_ValveResults.Count) * 0.02f;
        return returnValue;
    }</valvedata>

锁定时间"是"ValveData"对象的一个​​浮动对象，该对象被插入到m_ValveResults列表中.

而已.任何帮助将不胜感激.谢谢

[修改:如果您添加< pre lang ="cs">在代码和</pre>之前代码后，它将为您设置格式！]

the "Latch Time" is a float object of the "ValveData" object which is inserted into the m_ValveResults list.

thats it. any help would much be appreciated. Thanks

[Modified: if you add <pre lang="cs"> before the code and </pre> after the code, it will format it for you!]

推荐答案

一个简单的Google搜索C#和标准差的方法如下:

A simple google search of c# and standard deviation gave this:

private double getStandardDeviation(List<double> doubleList)
{
   double average = doubleList.Average();
   double sumOfDerivation = 0;
   foreach (double value in doubleList)
   {
      sumOfDerivation += (value) * (value);
   }
   double sumOfDerivationAverage = sumOfDerivation / doubleList.Count;
   return Math.Sqrt(sumOfDerivationAverage - (average*average));
}

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