用户控件中的数组 [英] array in user control

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本文介绍了用户控件中的数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

此代码是正确的还是有任何错误.请帮助....

在用户控制中:

Is this code is correct or have any mistake.Plz help....

in user control:

private Point[] _pin1PointPath = new Point[4];      
private Point[] _pin2PointPath = new Point[4];      
public Point[] pin1PointPath       
{           
   get { return _pin1PointPath; }       
}       
public Point[] pin2PointPath       
{           
   get { return _pin2PointPath; }       
}







public void setInput()       
{           
   if (temp_StaticVariable.staticVariable.ps_inputpinNo2 == 1)           
        {              
             /////....             
               _pin1PointPath = ps_Path;            
             ///...         
        }           
   else
        {   
           /////....          
          _pin2PointPath = ps_Path; 
           .....          
        }       
}




在主页中:




In main page:

vAnd[i].setInput();
///....





实际上,这两个变量的行为都像静态变量...

我听不懂我也用过brekpoint.所有vAnd仅对这些变量具有相同的值.





actually these both variable behaving like a static variable...

I am not able to understand. i used brekpoint also. all vAnd have same value for only these variable.

推荐答案

朋友,

尝试一下,
hi friend,

Just try with this,
private Point[] _pin1PointPath = new Point[4];      
private Point[] _pin2PointPath = new Point[4];      
public Point[] pin1PointPath       
{           
   get { return _pin1PointPath[number]; }       
}       
public Point[] pin2PointPath       
{           
   get { return _pin2PointPath[number]; }       
}


public void setInput()       
{           
   if (temp_StaticVariable.staticVariable.ps_inputpinNo2 == 1)           
        {              
             /////....             
               _pin1PointPath[number] = ps_Path;            
             ///...         
        }           
   else
        {   
           /////....          
          _pin2PointPath[number] = ps_Path; 
           .....          
        }       
}



谢谢,
Mahesh Patel



Thanks,
Mahesh Patel


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